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3 years ago

(5x ² +1) (2x + 3) - 2 x (5²-3)

Mathematics

1 answer:

kotegsom [21]3 years ago

6 0

Answer:

y = 3 suh slid este ob cine este a, b și g au nevoie de acel kinfo pentru a termina

Step-by-step explanation:

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Please help me with this math problem

astraxan [27]

Answer:

E. y = 2/3x

Step-by-step explanation:

You need to make an equation in slope-intercept form.

First, you need to find the slope. You can do this by taking two points and dividing the difference of the y's by the difference of the x's. I will use the first two points, but you can pick whichever points you want and still get the right answer. Also, the values in the left column will be x's, and the values in the right column will be y's.

8 - 2 = 6

12 - 3 = 9

6/9 = 2/3

The slope is 2/3. The only equation with this value is E.

6 0

3 years ago

Simplify to create an equivalent expression 8(10-6q)+3(-7q-2)

Temka [501]

Answer:

74-69q

Step-by-step explanation:

$8(10-6q)+3(-7q-2)\\\\80-48q-21q-6\\\\80-69q-6\\\\80-6-69q\\\\\boxed{74-69q}$

This can also be -69q + 74.

Hope this helps.

4 0

3 years ago

Use the substitution u = tan(x) to evaluate the following. int_0^(pi/6) (text(tan) ^2 x text( sec) ^4 x) text( ) dx

Rudiy27

If we use the substitution $u = \tan x$ , then $du = \sec^2 {x}\ dx$ . If you try substituting just $u$ and $du$ into the integrand, though, you'll notice that there's a $\sec^2x$ left over that we have to deal with.

To get rid of this problem, use the identity $\tan^2 x + 1 = \sec^2 x$ and substitute in the left side of the identity for the extra $\sec^2x$ , as shown:

$\int\limits^{\pi/6}_0 {tan^2 x \ sec^4 x} \, dx$
$\int\limits^{\pi/6}_0 {tan^2 x \ (tan^2 x + 1) \ sec^2 x} \, dx$

From there, we can substitute in $u$ and $du$ , and then evaluate:

$\int\limits^{\pi/6}_0 {tan^2 x \ (tan^2 x + 1) \ sec^2 x} \, dx$
$\int\limits^{\frac{1}{\sqrt{3}}}_0 {u^2(u^2 + 1)} \, du$
$\int\limits^{\frac{1}{\sqrt{3}}}_0 {u^4 + u^2} \, du$
$= \left.\frac{u^5}{5} + \frac{u^3}{3}\right|_0^\frac{1}{\sqrt{3}}$
$= (\frac{(\frac{1}{\sqrt{3}})^5}{5} + \frac{(\frac{1}{\sqrt{3}})^3}{3}) - (\frac{(0)^5}{5} + \frac{(0)^3}{3})$
$= \frac{1}{45\sqrt{3}} + \frac{1}{9\sqrt{3}} = \frac{6}{45\sqrt{3}} = \bf \frac{2}{15\sqrt{3}}$

8 0

3 years ago

Plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz help

Tema [17]

Answer:

Give me Brainiest answer to say thanks! :D

7 0

3 years ago

Read 2 more answers

Find the slope of the two points: 2 -4, 6,-7

ASHA 777 [7]

Answer:

-3/4 or -0.75

Step-by-step explanation:

-7- (4)= -3

6-2=4

-3/4

(use y2-y1/x2-x1)

6 0

3 years ago