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Nimfa-mama [501]
3 years ago
9

Bottled Juice Canned Juice Time (minutes) Cases packaged V 110 100 90 80 2 Cases 92 70 60 50 40 30 20 10 3 138 184 1 2 3 4 5 6 7

8 9 10 11 Minutes Fill in the blanks to compare the unit rates at which the cases are filled. I 1. What is the unit rate for bottled juice, in cases per minute? Explain how you found this unit rate. Write your answer in the space below. 2. what is the unit rate for canned juice, in cases per minute? explain how you found this unit rate. 3. are cans or bottles packaged at a faster rate?​
Mathematics
1 answer:
Leviafan [203]3 years ago
7 0

Answer:

320  

Step-by-step explanation:

hope this helps :)

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Answer: -8,6

Step-by-step explanation:

3 0
2 years ago
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The radius of the circle is increasing at a rate of 2 meters per minute and the sides of the square are increasing at a rate of
Lunna [17]

Answer:

Change in area=24\pi-48

Step-by-step explanation:

Let s will be the side of square and r will be the radius of circle.

Then two given conditions are

1)dr/dt=2 m/s

2)ds/dt=1 m/s

Area enclosed=(Area of square)-(Area of circle)

Area of square=s^{2}

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At s=24,and r=6

dA/dt=2(\pi)(6)(2)-2(24)(1)

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6 0
3 years ago
Find the value of x, rounded to the nearest tenth.<br> Correct answers only please..
agasfer [191]
Sin(35) = Opp./Hypo
sin(35) = 18/x
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4 0
3 years ago
If x+y=6 and xy =2find x³+y³(please help me fast with explanation also please) T^T​
Maurinko [17]

Answer: x³+y³=180

Step-by-step explain:                                                                                            let's remember the formula                                                                                 x³+y³=(x+y)(x²-xy+y²) and also  x³+y³=(x+y)³-3xy(x+y)                                              then                                                                                      \displaystyle\boldsymbol{ x^3+y^3=\underbrace{(x+y)^3}_{6}-3\underbrace{xy}_{2}\underbrace{(x+y)}_6}=\\\\6^3-3\cdot 2\cdot 6=216-36=180                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                

6 0
3 years ago
The graph of a quadratic function passes through the points (-1,0), (-2,0), and (0,2). Write the quadratic function in general f
ddd [48]

Answer:

f(x)=x^2+3x+2

Step-by-step explanation:

step 1

we have the points

(-1,0), (-2,0), and (0,2)

Plot the points

using a graphing tool

see the attached figure

The graph of a quadratic function must be a vertical parabola open upward

The vertex is a minimum

The quadratic function in general form is equal to

f(x)=ax^2+bx+c

Substitute the value of x and the value of y of each given ordered pair in the general equation and solve for a,b and c

(0,2)

For x=0, y=2

substitute

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c=2

(-1,0)

For x=-1, y=0

substitute

0=a(-1)^2+b(-1)+2

0=a-b+2 ----> a=b-2 ----> equation A

(-2,0)

For x=-2, y=0

substitute

0=a(-2)^2+b(-2)+2

0=4a-2b+2 ----> equation B

we have the system

a=b-2 ----> equation A

0=4a-2b+2 ----> equation B

substitute equation A in equation B

0=4(b-2)-2b+2

solve for b

0=4b-8-2b+2

2b=6

b=3

Find the value of a

a=3-2=1

therefore

The quadratic function in general form is equal to

f(x)=x^2+3x+2

see the attached figure N 2 to better understand the problem

7 0
3 years ago
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