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a_sh-v [17]
3 years ago
6

The ratio of 3 less than k to 2 more than k

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
5 0

We will find that the ratio of 3 less than k to 2 more than k is:

(k - 3):(k + 2)

The ratio between two numbers A and B can be written as:

A:B

This is the ratio of A to B

and

B:A

Is the ratio of B to A.

Then for the ratio of 3 less than k to 2 more than k we have:

"3 less than k" is: k - 3

"2 more than k" is: k+ 2

Then the ratio is:

(k - 3):(k + 2)

if you want to learn more, you can read:

brainly.com/question/13419413

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Studentka2010 [4]
It would be: 6 1/4 * 1 5/7
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Hope this helps!
4 0
3 years ago
Suppose we have a right triangle with legs of length a and b and hypotenuse of length c. Suppose b=3 and c=5. Then a= , For the
ANTONII [103]

Answer:

Length of right-angle  triangle 'a' = 4

b)

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  b = 3 and hypotenuse c = 5

Given ΔABC  is a right angle triangle

By using pythagoras theorem

        c² = a² + b²

  ⇒ a² = c² - b²

 ⇒  a² = 5²-3²

          =25 - 9

      a² = 16

⇒   a = √16 = 4

The sides of right angle triangle  a = 4 ,b = 3 and c = 5

<u><em>Step(ii):-</em></u>

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

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Step-by-step explanation:

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