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2 years ago

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A math teacher gave her class two tests. Twenty-five percent of the class passed both tests and 42 percent of the class passed o

nly the first test. What percent of the students who passed the first test also passed the second?

1 answer:

Norma-Jean [14]2 years ago

4 0

25% of the class who passed the first test also passed the second

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Which set is closed under subtraction?

siniylev [52]

Third one is correct

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2 years ago

Whats the surface area of the prism below,and please explain how you got the answer :)

nevsk [136]

Answer: 480 units^2

IN DEPTH EXPLANATION TO HELP YOU FOR FUTURE PROBLEMS:

Front:
b*h/2 = sa
12*5/2 = 30
Front = 30 units^2

Back:
b*h/2 = sa
12*5/2 = 30
Back = 30 units^2

Right:
w*l = sa
14*13 = 182 units^2
Right: 182 units*2
(figures out the length by using
pythagorean theorem)

Left:
w*l = sa
5*14 = 70 units^2
Left: 70 units^2

Bottom:
w*l = sa
12*14 = 168 units^2

ADD ALL THE UNITS:
168 + 70 + 182 + 30 + 30 = 480

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2 years ago

k0ka [10]

5x + 2y = 7 . . . (1)
y = x + 1 . . . (2)
Putting (2) into (1) gives
5x + 2(x + 1) = 7 => 5x + 2x + 2 = 7 => 7x = 7 - 2 = 5 => x = 5/7
From (2) y = 5/7 + 1 = 12/7

Therefore, solution is {(5/7, 12/7)}

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2 years ago

Solve the following two-step problems -5m - 4 = 4m

Musya8 [376]

Answer:

0.444

Step-by-step explanation:

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2 years ago

Read 2 more answers

The average daily volume of a computer stock in 2011 was ų=35.1 million shares, according to a reliable source. A stock analyst

Shtirlitz [24]

Answer:

a

The null hypothesis is $H_o : \mu = 35 .1 \ million \ shares$

The alternative hypothesis $H_a : \mu \ne 35.1\ million \ shares$

b

The 95% confidence interval is $27.475 < \mu < 37.925$

Step-by-step explanation:

From the question the we are told that

The population mean is $\mu = 35.1 \ million \ shares$

The sample size is n = 30

The sample mean is $\= x = 32.7 \ million\ shares$

The standard deviation is $\sigma = 14.6 \ million\ shares$

Given that the confidence level is $95\%$ then the level of significance is mathematically represented as

$\alpha = 100-95$

$\alpha = 5\%$

=> $\alpha = 0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table

The value is $Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{ \sigma }{\sqrt{n} }$

substituting values

$E = 1.96 * \frac{ 14.6 }{\sqrt{30} }$

$E = 5.225$

The 95% confidence interval confidence interval is mathematically represented as

$\= x -E < \mu < \= x +E$

substituting values

$32.7 - 5.225 < \mu < 32.7 + 5.225$

$27.475 < \mu < 37.925$

6 0

2 years ago