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3 years ago

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1. a baker had 10 sacks containing the following amounts of flour: 4 1/2 kg , 31/4 kg ,2 1/2 kg ,2 1/2 kg , 4 kg ,3 1/4 kg ,4 1/

4 kg , 5 kg , 2 1/2 kg , 3 1/4 kg
2. plot the measurements on a line plot give the line plot a title and label the axis

3. if the baker redistributed the flour equally among the ten bags how much flour would be in each bag explain your answer

1 answer:

OleMash [197]3 years ago

3 0

Baker's Flour in kg Y x x A x x X x x x x x x I ----------------------------------------------------------- S 2 1/2 3 1/4 4 4 1/4 4 1/2 5 X axis It would be 3.5 in each bag after the baker redistributes the flour. This is because the total flour would be 35 kg. 35 divided by 10 is 3.5 kg of flour in each bag.

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CaHeK987 [17]

Answer:

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Step-by-step explanation:

Given

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$Midpoint: (5,2)$

Required

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Let Midpoint be represented by (x,y);

(x,y) = (5,2) is calculated as thus

$(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$

So

$x = \frac{x_1 + x_2}{2}$ and $y = \frac{y_1 + y_2}{2}$

Where $(x_1,y_1) = (-6,2)$ and $(x,y) = (5,2)$

So, we're solving for $(x_2,y_2)$

Solving for $x_2$

$x = \frac{x_1 + x_2}{2}$

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$5 = \frac{-6 + x_2}{2}$

Multiply both sides by 2

$2 * 5 = \frac{-6 + x_2}{2} * 2$

$10 = -6 + x_2$

Add 6 to both sides

$6 + 10 = -6 +6 + x_2$

$x_2 = 16$

Solving for $y_2$

$y = \frac{y_1 + y_2}{2}$

Substitute 2 for y and 2 for y₁

$2 = \frac{2 + y_2}{2}$

Multiply both sides by 2

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$4 = 2 + y_2$

Subtract 2 from both sides

$4 - 2 = 2 - 2 + y_2$

$y_2 = 2$

$(x_2,y_2) = (16,2)$

Hence, the coordinates of the other end is $(16,2)$

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3 years ago

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Answer:

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Dafna11 [192]

My answer isn't in your choices so it's probably wrong, but hopefully my approach can give you hints.

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