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ollegr [7]
3 years ago
11

Can u help me with 2/3/4 I didn't understand

Mathematics
2 answers:
katovenus [111]3 years ago
8 0
You have to fraw sticks as the 10's for example #2 prtend thise are the sticks.(I)
IIII 4 tens in 42 the circles as ones  O O SO,IIII00
lions [1.4K]3 years ago
7 0
Don't really understand what you want help from
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Mittens, a baby kitten, gained 120 grams of weight in 1/3 of a month. If Mittens kept growing at this rate, how much weight woul
dlinn [17]

Answer:

Step-by-step explanation:

Given

A baby kitten, gained 120 grams of weight in 1/3 of a month.

he gain in 1 month

Solution

1/3 month =120gram weight

1 month =120×3

=360 gram is the answer

6 0
2 years ago
Just having lil problem with this math problem if anyone can help me please solving. thanks
Cloud [144]
1-2 is right
3 you have to draw a shape and then put 3 lines then shade in one
number 4 you have to draw a shape again but put 8 lines through then shade 1
5 your answer is 1/8
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3 years ago
Identify the values of the variables. Give your answers in simplest radical form. HELP ASAP!!
kumpel [21]

Answer:

B

Step-by-step explanation:

Since the triangle is right use the sine/ tangent ratios to solve for x and y

note sin60° = \frac{\sqrt{3} }{2} and tan60° = \sqrt{3}

sin60° = \frac{opposite}{hypotenuse} = \frac{3\sqrt{6} }{y}

ysin60° = 3\sqrt{6}

y × \frac{\sqrt{3} }{2} = 3\sqrt{6}

multiply both sides by 2 and divide by \sqrt{3}

y v= 6\sqrt{\frac{6}{3} } = 6\sqrt{2}

tan60° = \frac{opposite}{adjacent} = \frac{3\sqrt{6} }{x}

xtan60° = 3\sqrt{6}

x × \sqrt{3} = 3\sqrt{6}

divide both sides by \sqrt{3}

x = 3\sqrt{\frac{6}{3} } = 3\sqrt{2}


8 0
3 years ago
Read 2 more answers
A fair die with sides numbered 1, 2, 3, 4, 5, and 6 is to be rolled until a number greater than 4 first appears. what is the pro
AnnyKZ [126]
First two rolls have to be 1-4 that is 2/3 chance twice and the third can be 4or 5
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2/3*2/3*2/3*1/3

So the solution is : P=2/3*2/3*1/3 + 2/3*2/3*2/3*1/3
7 0
3 years ago
It costs $2.50 to rent a pair of bowling shoes and $1.75 for each game bowled.
garri49 [273]
I think it would be $77.00
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3 years ago
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