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kiruha [24]
3 years ago
10

Can someone tell me what number 60 is?

Mathematics
1 answer:
Marta_Voda [28]3 years ago
4 0
It is a number called 60
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Consider this quadratic equation:
zhenek [66]

Answer:

a=2

b=0

c=12

Step-by-step explanation:

The standard form of a quadratic equation is ax²+bx+c=0

Here's the given equation:

2x²+12=0

You might notice that the term bx is not there (there is just ax² and c). That means that b is 0.

The term 2x² is the term ax² in this equation. The coefficient in the term is 2, so that means that a is 2

12 has no variable, so that means it'll be c in the equation.

Hope this helps!

6 0
3 years ago
Using the given points and line, determine the slope of the line. (1, 2) and (2, 1) slope = 2 slope = 1 slope = -1
Bas_tet [7]

Answer:

-1

Step-by-step explanation:

Slope formula: (y₂ - y₁) / (x₂ - x₁)

= (2 - 1) / (1 - 2)

= -1

8 0
3 years ago
A movie was 3 1/2 hours long if Lilly turned of the movie off 1/4 of the way through how much time did she spend watching
Nuetrik [128]

Answer:

7/8 of an hour

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Anything helps please help me!
dimaraw [331]
5 1/2 = 11/2
11/2 x 3/4 = 33/8 = 4 1/8
answer is B. 4 1/8
8 0
3 years ago
Determine if the matrix below is invertible. Use as few calculations as possible. Justify your answer. [Start 4 By 4 Matrix 1st
Len [333]

Answer:

Yes, it is invertible

Step-by-step explanation:

We need to find in the matrix determinant is different from zero, since iif it is, that the matrix is invertible.

Let's use co-factor expansion to find the determinant of this 4x4 matrix, using the column that has more zeroes in it as the co-factor, so we reduce the number of determinant calculations for the obtained sub-matrices.We pick the first column for that since it has three zeros!

Then the determinant of this matrix becomes:

4\,*Det\left[\begin{array}{ccc}1&4&6\\0&3&8\\0&0&1\end{array}\right] +0+0+0

And the determinant of these 3x3 matrix is very simple because most of the cross multiplications render zero:

Det\left[\begin{array}{ccc}1&4&6\\0&3&8\\0&0&1\end{array}\right] =1 \,(3\,*\,1-0)+4\,(0-0)+6\,(0-0)=3

Therefore, the Det of the initial matrix is : 4 * 3 = 12

and then the matrix is invertible

4 0
3 years ago
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