HELP ME HELP ME !!

The sears tower in Chicago is 1,450 feet tall. A model of the tower is 24 inches tall. What is the ratio of the height of the mo

leonid [27]

Answer:

1450:24

reduced: 725:12

Step-by-step explanation:

3 0

4 years ago

let a function F:A➡️B be defined by f(x)=x+1÷2x-1 with A={-1,0,1,2,3,4} and B= {-1,0,4/5,5/7,1,2,3,}.Find the range of f. plzzzz

lidiya [134]

Answer:

Range: {-1, 0, 5/7, 4/5, 1, 2}

Step-by-step explanation:

We know that:

f(x) = (x + 1)/(2x - 1)

And:

f: A ⇒ B

where:

A={-1,0,1,2,3,4}

B= {-1,0,4/5,5/7,1,2,3,}

We want to find the range of f(x).

The range of f(x) will be the set of the outputs of f(x) (and because f goes from A to B, we will only take the outputs that belong to B).

Then we only need to evaluate all the values of A in f(x), and see if the output belongs to B.

we have:

f(x) = (x + 1)/(2x - 1)

f(-1) = (-1 + 1)/(2*-1 - 1) = 0 (this does belong to B)

f(0) = (0 + 1)/(2*0 - 1) = -1 (this does belong to B)

f(1) = (1 + 1)/(2*1 - 1) = 2 (this does belong to B)

f(2) = (2 + 1)/(2*2 - 1) = 1 (this does belong to B)

f(3) = (3 + 1)/(2*3 - 1) = 4/5 (this does belong to B)

f(4) = (4 + 1)/(2*4 - 1) = 5/7 (this does belong to B)

So the range of f(x) is the set with all these outputs, which is:

Range: {-1, 0, 5/7, 4/5, 1, 2}

5 0

3 years ago

The original line has the equation of y=-2x+8

enot [183]

The new equation of line that is perpendicular to the original that goes through the point (6, -1) in slope intercept form is $y = \frac{1}{2}x - 4$

<h3>Solution:</h3>

Given that original line has the equation of y = -2x + 8

We have to write a new equation that is perpendicular to the original that goes through the point (6, -1)

Let us first find slope of original line

The slope intercept form of line is given as:

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

On comparing the slope intercept form and given original equation, we get "m = -2"

Thus slope of original line "m" = -2

We know that product of slope of a line and slope of line perpendicular to it are always -1

slope of original line x slope of line perpendicular to it = -1

$\begin{array}{l}{-2 \times \text { slope of line perpendicular to it }=-1} \\\\ {\text { slope of line perpendicular to it }=\frac{1}{2}}\end{array}$