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VARVARA [1.3K]
3 years ago
8

PLEASE HELP ME ASAP!!!!! (Find the surface area of the prism)

Mathematics
2 answers:
Sveta_85 [38]3 years ago
7 0
I believe it is 672m
Leto [7]3 years ago
7 0
I think it is 672 m squared
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(used parentheses due to "forbidden language")
pishuonlain [190]

Answer:

Segment GD is half the length of segment HC​ ⇒ answer D

Step-by-step explanation:

* Look to the attached file

Download docx
7 0
3 years ago
When the smaller of two consecutive integers is added to two times the​ larger, the result is 35. Find the integers.
Aleonysh [2.5K]

x+2(x+1)=35

x+2x+2=35

3x=35-2=33

x=33/3=11

smaller number=11

larger number=11+1=12

4 0
3 years ago
Geometry solve for x​
gulaghasi [49]

Answer: b

Step-by-step explanation: the parallel proportionality theorem states that “if two or more parallel lines are intersected by two transversals, the parallel lines divide the transversals proportionally.” Therefore, you make a ratio and solve:

(4/2)=(6/x) and if you solve, x=3

now, 6+3=9, so 2x-11=9

if you solve for that, x=10

3 0
2 years ago
Please help with this SAT question. A solution gets Brainliest!
baherus [9]

Answer:

<h2>i think C</h2>

hope its help

C is my answer

3 0
2 years ago
US average math SAT scores follow a normal distribution with a mean of 505 and a standard deviation of 112. A sample of 64 enter
Hitman42 [59]

Answer:

The claim that the scores of UT students are less than the US average is wrong

Step-by-step explanation:

Given : Sample size = 64

           Standard deviation = 112

           Mean = 505

           Average score = 477

To Find : Test the claim that the scores of UT students are less than the US average at the 0.05 level of significance.

Solution:

Sample size = 64

n > 30

So we will use z test

H_0:\mu \geq 477\\H_a:\mu < 477

Formula : z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

z=\frac{505-477}{\frac{112}{\sqrt{64}}}

z=2

Refer the z table for p value

p value = 0.9772

α=0.05

p value > α

So, we accept the null hypothesis

Hence The claim that the scores of UT students are less than the US average is wrong

3 0
3 years ago
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