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3 years ago

Simplify the expression show all your work 18 / 2 x 3 over 5 - 2

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

6 0

Answer:

18÷2 × 3 / 5-2

9 ×3 / 3

27/3

tyvm this was my 100th answer :)

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Cancel the common factor of the numerator and the denominator and write specified expression

lisabon 2012 [21]

Step-by-step explanation:

Hello,

I hope you mean to cancel the common factor that exists in numerator and denominator,right.

so, Let's look for the common factor, 

here, the expression is, 

=4(x-2)/ (x+5)(x-2)

so, here we find the common factor is (x-2)

now, we have to cancel it. And after cancelling we get,

=4/(x+5)

Note:{ we cancel the common factor if the common factors are in multiply form.}

Hope it helps 

3 0

3 years ago

Help!!!!!!!!!!!!!!!!!!!!!!

zhuklara [117]

Answer:

see below

Step-by-step explanation:

9 ^-5 * 9^-3

When multiplying these we ADD the exponents:

9^-5 * 9^-3

= 9^(-5 + -3)

= 9 ^-8

= 1/9^8 Option A

2. 2^14 / 2^7 This is a division so we SUBTRACT the exponents:-

= 2^(14 - 7)

= 2^7 (answer)

3. If the triangle is a right angled one then it will obey Pythagoras Theorem so:-

13^ = x^2 + 5&2

x^2 = 13^2 - 5^2

x^2 = 144

x = 12 (answer)

4. The last choice is a crucial step.

The total area of the triangles is the same in both large squares so the area of the large square e^2 = a^2 + b^2 ( the 2 squares in the left side large square).

5 0

3 years ago

Determine the probability of having 2 girls and 3 boys in a 5-child family assuming boys and girls are equally likely.

Andrew [12]

The correct answer is 5/16.

5 0

3 years ago

The train travels at a constant speed. What is its speed? please hurry

jarptica [38.1K]

Answer:

300 km in hour are the answers

4 0

3 years ago

Paige launched a ball using a catapult she built. The height of the ball (in meters above the ground) ttt seconds after launch i

agasfer [191]

Answer:

1) Factor form : $h(t)=-5t(t-8)$

2) 8 second after launch.

Step-by-step explanation:

The height of the ball (in meters above the ground) t seconds after launch is modeled by

$h(t)=-5t^2+40t$

To find the time when ball hit the ground, we need to find the factor form of the given function.

$h(t)=-5t(t-8)$

When ball hi the ground, then height of the ball from the ground is 0.

$h(t)=0$

$-5t(t-8)=0$

Using zero product property, we get

$-5t=0\Rightarrow t=0$

$t-8=0\Rightarrow t=8$

Ball hit the ground at t=0 and t=8. It means ball hit the ground in starting and 8 second after launch.

5 0

3 years ago