in step 2 he made his first mistake
1/2(n-4)-3=3-(2n+3)
1/2n-4/2-3=3-(2n+3)
1/2n-2-3=3-(2n+3)
in the second step he put 5 instead of 2.
It is since it is a straight line when plotted in a graph
It is a quick response
- <u>Jan </u><u>purchased </u><u>1</u><u>4</u><u>0</u><u> </u><u>shares </u><u>of </u><u>stock </u><u>in </u><u>ABC </u><u>company </u><u>at </u><u>a </u><u>price </u><u>of </u><u>$</u><u>1</u><u>8</u><u>.</u><u>7</u><u>5</u><u> </u><u>per </u><u>share </u>
- <u>During </u><u>the </u><u>next </u><u>3</u><u> </u><u>days</u><u>, </u><u> </u><u>the </u><u>value </u><u>of </u><u>share </u><u>declined </u><u>by </u><u>$</u><u>1</u><u>.</u><u>0</u><u>0</u><u> </u><u>,</u><u> </u><u>$</u><u>1</u><u>.</u><u>7</u><u>5</u><u> </u><u>and </u><u>$</u><u>1</u><u>.</u><u>5</u><u>0</u>
- <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>a </u><u>share </u><u>of </u><u>ABC </u><u>stock </u><u>at </u><u>the </u><u>end </u><u>of </u><u>3</u><u> </u><u>days </u>
<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>
Cost of 1 share of ABC company = $18.75
<u>Therefore</u><u>, </u>
Cost of 140 shares purchased by Jan in the ABC company
<u>Now</u><u>, </u>
For next 3 days, the value of share declined
<u>Therefore</u><u>, </u>
The value of shares after 3 days will be
Hence, The value of share after 3 days will be $18.75 .
Step-by-step explanation:
ANOVA table Source SS df MS F
p-value Factor 1 12.00 1 12.000 1.20 .3153
Factor 2 8.00 2 4.000 0.40 .6870 Interaction 56.00 2 28.000 2.80 .1384
Error 60.00 6 10.000 Total 136.00 11
Since the p -value for Factor A is greater than 0.1, therefore Factor A is not significant. The p -value for Factor B is greater than 0.1, therefore Factor B is not significant. It should be noted that for P-value of both Factor and Factor B to be significant, each factor must not be greater than 0.1
27 divided by 3 = 9
9 times 5 = 45