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3 years ago

Tìm diện tích hình thang

Mathematics

1 answer:

djverab [1.8K]3 years ago

4 0

Answer:

Diện tích hình thang bằng trung bình cộng của 2 đáy nhân với chiều cao của nó. Trong đó: + S: Diện tích. + a,b: Lần lượt là độ dài 2 đáy.

Step-by-step explanation:

uhhh hope that helps:3

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T^2 +11t+30/t^2+5t-24 ÷ t^2+4t-21/t^2+10t+25

pogonyaev

Answer:

t^2 + 30t - 15/t^2 + 25

Step-by-step explanation:

7 0

3 years ago

Faiz's total online shipping bill comes to £45.71.

larisa [96]

Given:

Faiz's total online shipping bill comes to £45.71.

He then receives discount of £15.90.

To find:

How much does he have to finally pay after the discount?

Solution:

We have,

Amount of bill = £45.71

Discount amount = £15.90

Now,

Final payment = Amount of bill - Discount amount

= £45.71 - £15.90

= £29.81

Therefore, Faiz's have tp pay £29.81 after discount.

7 0

3 years ago

What is the area of this trapezoid? Enter your answer in the box.

WITCHER [35]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Pleaseeee help meeeee What is ∑n=125(3n−2) equal to?

vichka [17]

Answer:

$\sum_{n=1}^{25}(3n-2)=925]$

Step-by-step explanation:

The given series is $\sum_{n=1}^{25}(3n-2)$

The first term of this series is

$a_1=3(1)-2$

$a_1=3-2$

$a_1=1$

The second term is

$a_2=3(2)-2$

$a_2=6-2$

$a_2=4$

The common difference is

$d=4-1=3$

The sum of the first n-terms is given by;

$S_n=\frac{n}{2}[2a_1+d(n-1)]$

The sum of the first 25 terms of the series is

$S_{25}=\frac{25}{2}[2(1)+3(25-1)]$

$S_{25}=\frac{25}{2}[2+3(24)]$

$S_{25}=\frac{25}{2}(74)]$

$S_{25}=925]$

4 0

4 years ago

Read 2 more answers

F(x)=x^3+ax^2+bx+3 where a and b are constants. bx Given that when f (x) is divided by (x+2) the remainder is 7, (a) show that 2

Vlad1618 [11]

Part I - First synthetic division

You need to use synthetic division to come up with an expression for a and b:

(x + 2) is a factor, and the remainder is 7, so we can draw a synthetic division table...

coefficients = 1 for X^3; A for X^2; B for X^1; and 3

-2 | 1 A B 3

 -2 -2(A-2) 4(A-2)-2B

 1 (A-2) -2(A-2)+B 4(A-2)-2B + 3

Remainder = 7

So...

4(A-2)-2B + 3 = 7

4 * (A - 2) - 2B + 3 = 7

4A - 8 - 2B = 4

4A - 2B = 12

2A - B = 6
Proved

-------------------------------------------------------------------------------------------------------------------
Part II - Second Synthetic Division

We draw another synthetic division table, this time with (x - 1), so the number on the left hand side will be +1

1 | 1 A B 3

 1 (A+1) A+B+1

 1 (A+1) A+B+1 A+B+4

 Remainder = 4

So...

A + B + 4 = 4

A + B = 0

A = -B

-------------------------------------------------------------------------------------------------------------------
Part III - Solving for A and B with our two simultaneous equations

We know that A = -B and we also know that 2A - B = 6

Since we know that A is equal to -B We can substitute in A for -B, to get:

2A - B = 6

Therefore...

2A + A = 6

3A = 6

A = 2

Again, as we know that A = -B, and as we have found that A = 2, we can see:

A = -B

Therefore...

2 = -B

B = -2

So our final answer is A = 2, B = -2

Hopefully this answer is more useful than the last one, and isn't so confusing!

8 0

3 years ago