350 / 7 = 50
50 * 2 = 100
100 new members
100 / 10 = 10
10 * 3 = 30
30 are new female members
Answer:
3/5 has the smallest denominator
Step-by-step explanation:
Question:
There exist infinitely many common fractions a/b , where a > 0 and b > 0 and for which 3/5 < a/b< 2/3. Of these common fractions, which has the smallest denominator? Express your answer as a common fraction.
Solution
A Common fraction is a rational number written in the form: a/b. Where a and b are both integers.
The denominator and numerator in this case are greater than zero. That is, they are non zeros.
The least common denominator (LCD) of two non- zero denominators is the smallest whole number that is divisible by each of the denominators.
To find the smallest denominator between 3/5 and 2/3, we would convert the fractions to equivalent fractions with a common denominator by finding their LCM (lowest common multiple).
When comparing two fractions with like denominators, the larger fraction is the one with the greater numerator and the smaller fraction is one with the smaller numerator.
In our solution after comparing, the smaller fraction would have the smallest denominator.
Find attached the solution.
Answer:
rounding to the nearest tenth
Step-by-step explanation:
Answer: y=6x-12
Step-by-step explanation:
From the diagram above,
XZ = 10 in and OX = 10 in
we are to find length of OY
XZ is a chord and line OY divides the chord into equal length
Hence, ZY=YX= 5 in
Now we solve the traingle OXY
To find OY we solve using pythagoras theorem

applying values from the triangle above
![\begin{gathered} OX^2=XY^2+OY^2 \\ 10^2=5^2+OY^2 \\ 100=25+OY^2 \\ OY^2\text{ = 100 -25} \\ OY^2\text{ = 75} \\ OY\text{ = }\sqrt[]{75} \\ OY\text{ = }\sqrt[]{25\text{ }\times\text{ 3}} \\ OY\text{ = 5}\sqrt[]{3\text{ }}in \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20OX%5E2%3DXY%5E2%2BOY%5E2%20%5C%5C%2010%5E2%3D5%5E2%2BOY%5E2%20%5C%5C%20100%3D25%2BOY%5E2%20%5C%5C%20OY%5E2%5Ctext%7B%20%3D%20100%20-25%7D%20%5C%5C%20OY%5E2%5Ctext%7B%20%3D%2075%7D%20%5C%5C%20OY%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B75%7D%20%5C%5C%20OY%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B25%5Ctext%7B%20%7D%5Ctimes%5Ctext%7B%203%7D%7D%20%5C%5C%20OY%5Ctext%7B%20%3D%205%7D%5Csqrt%5B%5D%7B3%5Ctext%7B%20%7D%7Din%20%5Cend%7Bgathered%7D)
Therefore,
Length of OY =