Each coin will either land as a head or a tail. - 2 possible results.
for 5 coins its 2*2*2*2*2 = 32 different results.
Suppose we wish to determine whether or not two given polynomials with complex coefficients have a common root. Given two first-degree polynomials a0 + a1x and b0 + b1x, we seek a single value of x such that
Solving each of these equations for x we get x = -a0/a1 and x = -b0/b1 respectively, so in order for both equations to be satisfied simultaneously we must have a0/a1 = b0/b1, which can also be written as a0b1 - a1b0 = 0. Formally we can regard this system as two linear equations in the two quantities x0 and x1, and write them in matrix form as
Hence a non-trivial solution requires the vanishing of the determinant of the coefficient matrix, which again gives a0b1 - a1b0 = 0.
Now consider two polynomials of degree 2. In this case we seek a single value of x such that
Hope this helped, Hope I did not make it to complated
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Answer:
d = 3/4
Step-by-step explanation:
2.5 - d = 1.75
-2.5 -2.5
------------------
-d = -0.75
d = 0.75
d = 3/4
First we are going to group the terms that contains the common factor
in one parenthesis, and the other ones in another parenthesis:
Notice that our the terms in our first parenthesis have a common factor
, and the terms in our second one have the common factor
. Lets factor those out:
Now we have a common factor
in both terms, so we can factor those out as well:
We can conclude that the completely factored expression ordered alphabetically is
.
Answer:
Step-by-step explanation:
