<span>The integral of (x^2 + 6x)dx is 1/3x^3 + 3x^2 + c.
Because this is not an integration with specific bounds, you must include a constant at the end.
In general, to integrate, add 1 to the exponent of x and then whatever number is the exponent of x, divided the number in front of x by that.</span>
I believe x is 0 because if we assume y and x are 0 then 0=0 and 0= 5 x 0
Answer:
3
Step-by-step explanation:
3*3*3*3=81
that's my answer
Your answer for this one is A....use the distributive property
I think the answer would be D
