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Anettt [7]
3 years ago
9

PLEASE HELP WILL MARK BRAINLIEST!

Mathematics
1 answer:
polet [3.4K]3 years ago
3 0

Answer:

A

Step-by-step explanation:

2(1)+ 1(2)+ 2(3)+2(4)+ 3(5)/ 10

= 2+2+6+8+15/10

= 33/10

= 3.3

or A

if my answer helps please mark as brainliest.

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Two 6-sided dice are tossed simultaneously. what is the probability of the total being equal to 9?
prohojiy [21]
Total number of outcomes = 36

Number of outcomes with total being 9 = 4
(6, 3) (5,4), (4, 5) (3, 6)

P(equal to 9) = 4/36 = 1/9

Answer: 1/9 (Answer A)
3 0
3 years ago
Use division instead of the images to divide 18 by 4. What is the quotient of the division? What is the remainder?
musickatia [10]

18 \div 4
First see what 4 could go by and the answer closest to 18 that is not more than the answer is the first number of the answer.
4×1=4
4×2=8
4×3=12
4×4=16
In this case 4 is the first number of the answer because if you fo 4 by 5 it equals 20 , which is more than the answer
4×5=20
after that , you subtract the answer, 18 minus 16 which is 2 because nothing times 4 equals 2
So the remainder is 2/4 or .50
If you have any questions about this please don't hesitate to ask me

4 0
3 years ago
Explain step by step now to arrive at a single rational number to represent the following expression
tatyana61 [14]

Answer:

shhheeeeeeesh that's is hard good luck

7 0
2 years ago
A computer chess game and a human chess champion are evenly matched. They play twelve games. Find probabilities for the followin
sleet_krkn [62]

Answer:

The probability that they each win six games is 0.225.      

Step-by-step explanation:

Given : A computer chess game and a human chess champion are evenly matched. They play twelve games.

To find : The probability that they each win six games?

Solution :

Applying binomial distribution,

Here n=12 and p=0.5

P(X=k)=\frac{n!}{k!(n-k)!}\times p^k\times (1-p)^{n-k}

The probability that they each win six games is k=6.

P(X=6)=\frac{12!}{6!(12-6)!}\times 0.5^6\times (1-0.5)^{12-6}

P(X=6)=\frac{12\times 11\times 10\times 9\times 8\times 7\times 6!}{6\times 5\times 4\times 3\times 2\times 6!}\times 0.015625\times 0.015625

P(X=6)=11\times 2\times 3\times 2\times 7\times 0.015625\times 0.015625

P(X=6)=0.225

Therefore, The probability that they each win six games is 0.225.

3 0
3 years ago
Please solve all if you do I’ll give brainly
riadik2000 [5.3K]

Answer:

1. 330,400

2. 0.000084

3. 2,100

4. 7.823 x 10^9

7 0
2 years ago
Read 2 more answers
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