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2 years ago

PLEASE HELP WILL MARK BRAINLIEST!

Mathematics

1 answer:

polet [3.4K]2 years ago

3 0

Answer:

Step-by-step explanation:

2(1)+ 1(2)+ 2(3)+2(4)+ 3(5)/ 10

= 2+2+6+8+15/10

= 33/10

= 3.3

or A

if my answer helps please mark as brainliest.

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cestrela7 [59]

The 3 inside angles of a triangle need to add up to 180 degrees.

You have two angles of 104 and 36.

A = 180 - 104 - 36 - 40

The answer is 40

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3 years ago

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kherson [118]

Answer: IXL

Step-by-step explanation:

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2 years ago

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The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

2 years ago

63 first-year teachers and 27 experienced teachers attended a school staff meeting. What percentage of the teachers in the meeti

nexus9112 [7]

Answer: 70%

Step-by-step explanation:

Step 1:

Total number of teachers = 63 + 27

= 90

Step 2:

The percentage of the teachers in the meeting were first-year teachers:

(63 ÷ 90) × 100 = 70%

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2 years ago

The figure below shows a graph of the function of f(x) in the coordinate plane

Lana71 [14]

Answer:I think one is x

Step-by-step explanation:

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2 years ago