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BlackZzzverrR [31]
3 years ago
13

F – 6 = -2f + 3(f – 2) show your work please

Mathematics
1 answer:
Evgen [1.6K]3 years ago
8 0

f - 6 = -2f + 3(f - 2)

f - 6 = -2f + 3f - 6

f + 2f - 3f = -6 + 6

0 = 0

Every number is solution this equation.

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If a town with a population of 10,000 doubles every 14 years, what will the population be in 42 years and is it modeled by a lin
madreJ [45]
This is an exponential function.
The starting population is: 10,000 and it doubles every 14 years.
In 42 years ( 42 : 14 = 3 ) the population doubles 3 times.
The equation ( exponential ) is :
y = 10,000 * 2^n
In this case: n = 3
y = 10,000 * 2 ^3 = 10,000 * 8 = 80,000
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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
Finding an Equation of a Tangent Line In Exercise, use implicit differentiation to find an equation of the tangent line to the g
Karo-lina-s [1.5K]

Answer:

y=\frac{4}{3}-\frac{x}{3e}

Step-by-step explanation:

Equation of tangent line of given function at (e,1) is found by implicitly differentiating the given function w.r.to x

y^{2}+ln(xy)=2\\\\y^{2}+ln(x)+ln(y)=2\\\\\frac{d}{dx}(y^{2}+ln(x)+ln(y))=\frac{d}{dx}(2)\\\\2y\frac{dy}{dx}+\frac{1}{x}+\frac{1}{y}\frac{dy}{dx}=0\\\\\frac{dy}{dx}(2y+\frac{1}{y})=-\frac{1}{x}\\\\\frac{dy}{dx}=-\frac{y}{x(2y^{2}+1)}\\\\at (e,1)\\\\\frac{dy}{dx}=-\frac{1}{e(2+1)}\\\\\frac{dy}{dx}=\frac{1}{3e}

Equation of tangent line is

y-y₁=m(x-x₁)

at (e,1)

y-1=-\frac{1}{3e}(x-e)\\\\y=1-\frac{1}{3e}(x-e)\\\\y=1+\frac{1}{3}-\frac{x}{3e}\\\\y=\frac{4}{3}-\frac{x}{3e}\\

6 0
4 years ago
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Answer:

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Step-by-step explanation:

8 0
3 years ago
What's the sum of an infinite geometric series if the first term is 156 and the common ratio is 2∕3?
DENIUS [597]

Answer:

468

Step-by-step explanation:

Formula for infinite sum of geometric series is;

S_∞ = a1/(1 - r)

Where;

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We are given;

a1 = 156

r = ⅔

Thus;

S_∞ = 156/(1 - ⅔)

S_∞ = 156/(⅓)

S_∞ = 468

4 0
3 years ago
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