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natka813 [3]
3 years ago
5

5/8x - 11/2 = 3/4 what does the x equal ?

Mathematics
1 answer:
Verizon [17]3 years ago
6 0

Answer:

x=10

Step-by-step explanation:

5/8x - 11/2 = 3/4

Multiply each side by 8 to clear the fractions

8(5/8x - 11/2 = 3/4)

5x - 44 = 6

Add 44 to each side

5x-44+4= 6+4

5x= 50

Divide by 5

5x/5 = 50/5

x =10

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Help this makes no sense to me and its due in 1 day
Ganezh [65]

First we can find the line RT which is the square root of 40^2-32^2 which is equal to 24.

RT=24

Right Triangle Altitude Theorem Part: The measure of the altitude drawn from the vertex of the right angle of a right triangle to its hypotenuse is the geometric mean between the measures of the two segments of the hypotenuse.

The geometric mean of 32 and TS is 24, so set up equation.

2nd root or square root of 32*TS=24

32*TS=576

TS=18

QS=18+32=50

I hope this answer helped if you have any questions feel free  to ask me in the comments.

7 0
3 years ago
There is a bag with 50 popsicles inside. 5
Allisa [31]

Answer:

25%

Step-by-step explanation:

We know that there are ten purple popsicles. Together without the purple popsicles, there are 40 popsicles in total. Therefore there is a 10/40 chance to get purple. We need to turn this into a percentage so we do (10 / 40) x 100. This would equal to 25%, therefore, there is a 25% probability to get a purple popsicle.

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3 years ago
What is 15/36 in simplest form
Art [367]
5/12 is the simplest form of 15/36
5 0
3 years ago
Point Y is the midpoint of segment XZ. If XY = 2(3x +1) and YZ = 5x + 22, find the value of x.
Ede4ka [16]
<h3>Point Y is the midpoint of segment XZ. Then value of x is 20</h3>

<em><u>Solution:</u></em>

Given that,

<em><u>Point Y is the midpoint of segment XZ</u></em>

XY = 2(3x +1)

YZ = 5x + 22

To find: Value of x

Since, Point Y is the midpoint of segment XZ,

Therefore,

XY = YZ

2(3x + 1) = 5x + 22

6x + 2 = 5x + 22

6x - 5x = 22 - 2

<h3>x = 20</h3>

Thus, value of x is 20

6 0
3 years ago
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nydimaria [60]

Answer:

{ c  ∣  c ≠  2 , 12, -1, 0, c ∈ R }

Step-by-step explanation:

Considering the set

\left\{\left(2,\:8\right),\left(12,\:3\right),\:\left(c,\:4\right),\:\left(-1,\:8\right),\:\left(0,\:3\right)\right\}

As we know that

  • A function is said to be a relation if every x-value has one and only one y-value.

So, the value of c must not be equal to 2, 12, -1, 0 i.e. c ≠ 2, 12, -1, 0

Therefore,

                   { c  ∣  c ≠  2 , 12, -1, 0, c ∈ R }

7 0
3 years ago
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