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4 years ago

How do you find this out

Mathematics

1 answer:

andrew-mc [135]4 years ago

8 0

A. 13/15
b. 5/8
c. 4 11/12
d. 3 3/5

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Determine whether or not the two equations below have the same solution. In two or more complete sentences, explain your rationa

Dimas [21]

These equations do match up. All you have to do is find the solution to the first equation. After that, plug in that solution to the second equation. If it makes the equation true, then the equations match.

Hope this helps!

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3 years ago

Read 2 more answers

Find f.<br> Write your answer as an integer or as a decimal rounded to the nearest tenth.

Natalka [10]

Answer:

Just wanted to say someone already gave you an answer of 62.7° in this question when you asked it before, they also gave a pretty good explanation!

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3 years ago

Emily knows that the area of a rectangle is 54x9y8 square yards and that it’s length 6x3y4 yards. If she divides the area by the

Furkat [3]

Answer:

Width of the rectangle is: $\mathbf{Width= 9x^6 y^4}$

Option C is correct.

Step-by-step explanation:

Area of rectangle = $54x^9y^8$

Length of rectangle = $6x ^ 3y^4$

We need to find width of rectangle.

The formula used is:

$Area\:of\:rectangle=Length\times Width\\Width=\frac{Area\:of\:rectangle}{Length}$

Putting values in the formula to find Width of rectangle

$Width=\frac{Area\:of\:rectangle}{Length}\\Width=\frac{54x^9y^8}{6x^ 3y^4}$

Using the exponent rule: $\frac{a^m}{a^n}=a^{m-n}$

and simplifying the terms we get

$Width=\frac{54x^9y^8}{6x^3y^4}\\Width=9x^{9-3} \: y^{8-4}\\Width=9x^6 y^{4}$

So, Width of the rectangle is: $\mathbf{Width= 9x^6 y^4}$

Option C is correct.

6 0

3 years ago

A number was multiplied by 6 then increased by 3 and the result was 33

Nina [5.8K]

The number that you are trying to find is 5

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4 years ago

A mouse climbs up a well of 86 meters. It advances 14 meters during the night, but during the day it retreats 2. The mouse will

Deffense [45]

Step-by-step explanation:

we assume day and night are equally long.

and the mouse will start at night of day 1.

then, on day 2, it will first retreat 2 meters (during daylight) and then advance 14 meters (at night).

so, on every full day, the mouse will effectively advance 12 meters (-2 + 14 = 12).

with a starting value of 14 (the first night).

so, we are getting an arithmetic sequence

an = an-1 + c

c = 12 in our case.

a1 = 14

a2 = a1 + 12 = 14+12 = 26

a3 = a2 + 12 = a1 + 12 + 12 = 14 + 2×12 = 38

an = a1 + (n-1)×12 = 14 + 12(n-1)

at what n will it reach 86 ?

86 = 14 + 12(n-1) = 14 + 12n - 12 = 2 + 12n

84 = 12n

n = 7

so, on the 7th day the mouse will reach the surface (if we truly count the first starting night day 1 - this is up to your teacher, but I would).

7 0

2 years ago