Answer:
a+2b-d=1, 3, 5, 7
Step-by-step explanation:
(ax^2+bx+3)(x+d)
ax^3+bx^2+3x+adx^2+bdx+3d
ax^3+bx^2+adx^2+3x+bdx+3d=x^3+6x^2+11x+12
ax^3=x^3, a=1
bx^2+adx^2=6x^2
x^2(b+ad)=6x^2
b+ad=6
b+(1)d=6
b+d=6
------------
3x+bdx=11x
x(3+bd)=11x
3+bd=11
-----------------
b=6-d
3+(6-d)d=11
3+6d-d^2=11
3-11+6d-d^2=0
-8+6d-d^2=0
d^2-6d+8=0
factor out,
(d-4)(d-2)=0
zero property,
d-4=0, d-2=0
d=0+4=4,
d=0+2=2
b=6-4=2,
b=6-2=4.
------------------
a+2b-d=1+2(2)-2=1+4-2=5-2=3
-------------------
a+2(4)-4=1+8-4=9-4=5
-----------------------
a+2(2)-4=1+4-4=5-4=1
-----------------------
a+2(4)-2=1+8-2=9-2=7
Answer:2(x-3)2
Step-by-step explanation:
12x is the correct answer
Answer: -1
Step-by-step explanation:
f(t) = -2t + 3
f(-2) = -2 x -2 + 3 [ substituting the value]
f(-2) = -4 + 3
f(-2) = -1
15.
6 pachages
each pcage has 30
6*30=180 total
17 left over
how many used
used=total-left over
used=180-17
used=163
16. xy is 2 digit number
multiplules of 10 (whole multipules) always end with 0 so y=0
and has 3 as one of its factors
factors of 3 is 3,6,9,12
30,60,90 is answer
17.
30 in 9 parks
30 times 9
30=10 times 3
3*10*9
group the 3 and 9
10*(3*9)
3*9=27
10*(27)
270
15. 163
16. 30,60,90
17. see above, 270
