Answers:
5. x = 1
6. y = 11.5
Step-by-step explanation:
For question 5, you can use power of a point which describes the relationship of two secants intersecting inside a circle. You get the formula:
AC * CD = BC * CE
You can substitute the values you are given to get:
2 * 4 = x * 8
This gives you x = 1
For question 6, you can use another formula in power of a point that describes two secants intersecting in the exterior of a circle. You get the formula:
GH * GJ = GI * GK
Using segment addition postulate, you get:
GJ = GH + HJ = 5 + 16 = 21
GK = GI + IK = 6 + y --> y + 6
Now, substitute into the equation from power of a point:
5 * 21 = 6 * (y + 6)
105 = 6 * (y + 6)
17.5 = y + 6
y = 11.5
Answer: 6/12 are white, 3/12 are colored and 3/12 are albino.
Step-by-step explanation: If the horses are white and their parents are ccww (albino) and CCWw (white horse), according to Mendel's premises, they both must be CcWw, since the crossing provides one C from one parent and other c from the other parent, one W and the other w. Using Mendel's chess and the principle of independent segregation, the crossing between CcWw results in the following fenotypical ratio:
1/16 CCWW (lethal)
2/16 CCWw (white)
2/16 CcWW (lethal)
4/16 CcWw (white)
1/16 CCww (normal)
2/16 Ccww (normal)
2/16 ccWw (albino)
1/16 ccWW (lethal)
1/16 ccww (albino)
Excluding the 4 individuals that have the lethal locus, we have 6/12 that are white (2/12 + 4/12) and 3/12 (1/12 + 2/12) that are colored. Also, there are 3/12 of albino individuals as well.
♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️
The correct answer is (( D )) .
♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️
-(-2-5x)+(-2)=18
2+5x-2=18
5x=18
x=18/5=3.6
X + 5 + 11x = 12x + y
Simplify: 12x + 5 = 12x + y (We are adding x and 11x on the left side)
Subtract 12x from each side makes each zero.
5 = y
So we can plug in and test. I'm picking two random numbers to plug in for x. 10, and 82
x = 10, y = 5
10 + 5 + 11(10) = 12(10) + 5
125 = 125
x = 82, y = 5
82 + 5 + 11(82) = 12(82) + 5
989 = 989
So we verified y = 5
