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3 years ago

What form of deductive reasoning is used in the given argument?

Mathematics

2 answers:

mestny [16]3 years ago

7 0

Answer:

law of contrapositive

ankoles [38]3 years ago

5 0

Answer:

law of contrapositive

Step-by-step explanation:

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Solve 7x-2y=11 for y

Leni [432]

Answer:

y = 7/2x -11/2

Step-by-step explanation:

7x-2y=11

Subtract 7x from each side

7x-2y -7x = -7x+11

-2y = -7x+11

Divide each side by -2

-2y/-2 = -7x/-2 +11/-2

y = 7/2x -11/2

8 0

3 years ago

Read 2 more answers

Wal-Mart sells a case of 24 cans of Diet Coke for $6.88. To the nearest

shutvik [7]

Answer:

$0.29 cents

Step-by-step explanation:

6.88/24 = 0.28666666666 about 0.29

3 0

3 years ago

assume that a 150-pound person starts a diet loses 2 pounds per week for 15 weeks . write an equation modeling this situation

boyakko [2]

Weight = w
no. of weeks = n

w = 150 - 2n

8 0

3 years ago

Y = 100 (1- 1/2) ^t<br><br> decay or growth

charle [14.2K]

Answer:

Decay

Step-by-step explanation:

We are given an equation $y=100(1-0.5)^t$

We need to say about decay or growth of exponential function.

Exponential function: $y=a\cdot b^x$

Where,

a is initial value of exponential function.
b is decay or growth of function

For decay: 0<b<1

For growth: b>1

Now we rewrite the equation into this form

$y=100(1-0.5)^t$

Changes to

$y=100(0.5)^t$

Here, b=0.5 < 1

Therefore, The given function would be decay.

Thus, $y=100(1-0.5)^t$ is deacy.

8 0

4 years ago

Use the Laplace transformation to solve the given IVP.<br><br> y'-y=2sin3t, y(0)=0

maxonik [38]

Answer:

$y(t)=\frac{3}{5}e^t-\frac{3}{5}cost 3t-\frac{1}{5} sin3t$

Step-by-step explanation:

We are given that

y'-y=2 sin3t,y(0)=0

We have to solve given differential equation using Laplace transform

We know that L(y'-y)=L(2sin3t)

$sY(s)-y(0)-Y(s)= \frac{6}{s^2+9}$

$L(sinat)=\frac{a}{s^2+a^2}$

$Y(s)(s-1)=\frac{6}{s^2+9}$

$Y(s)=\frac{6}{(s^2+9)(s-1)}$

Using partial fraction

$\frac{6}{(s^2+9)(s-1)}=\frac{A}{s-1}+\frac{Bs+c}{s^2+9}$

$6=A(s^2+9)+(s-1)(Bs+C)$

s-1=0 then s=1

substitute s= 1 in equation

6=A(1+9)

$A=\frac{6}{10}=\frac{3}{5}$

Comparing coefficient of $s^2$ and s on both sides then we get

$A+B=0$

$B=-A=-\frac{3}{5}$

$-B+C=0$

$B=C=-\frac{3}{5}$

Substitute the values

Then, Y(s)= $\frac{3}{5}\frac{1}{s-1}+\frac{\frac{-3}{5} s-\frac{3}{5}}{s^2+9}$

Apply inverse transform then we get

$y(t)=\frac{3}{5}e^t-\frac{3}{5}cost 3t-\frac{1}{5} sin3t$

$L(cos at}=\frac{s}{s^+a^2}$ and $L(e^{at})=\frac{1}{s-a}$

7 0

4 years ago