Apply the Pyth Thm twice:
diagonal of base is sqrt(4^2+6^2).
Then the length of diagonal AB is L = [sqrt(4^2+6^2)]^2 + [sqrt(1)]^2
41 hours of class I guess so
Answer:
Step-by-step explanation:
6-3x=12-6x
Only one solution of x=2
The answer to your question is True.