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3 years ago

8

For questions 4-5, decide whether each table of values describes a function or not.

1 answer:

lara31 [8.8K]3 years ago

3 0

Answer:

Function

Step-by-step explanation:

Two different X's could equal the same Y value so this is a function. Remember if there's multiple of the same input (x) equalling different outputs (y) then it is not a function. If there's multiple inputs (x) equalling the same output (y) it's just coincidence and works.

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3 years ago

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Step-by-step explanation:

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nikitadnepr [17]

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4 years ago

Assume that the number of customers who arrive at a water ice stand follows the Poisson distribution with an average rate of 6.4

Nady [450]

Answer:

18.88% probability that three or four customers will arrive during the next 30 minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

Average rate of 6.4 per 30 minutes.

This means that $\mu = 6.4$

What is the probability that three or four customers will arrive during the next 30 minutes?

$P = P(X = 3) + P(X = 4)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 3) = \frac{e^{-6.4}*(6.4)^{3}}{(3)!} = 0.0726$

$P(X = 4) = \frac{e^{-6.4}*(6.4)^{4}}{(4)!} = 0.1162$

$P = P(X = 3) + P(X = 4) = 0.0726 + 0.1162 = 0.1888$

18.88% probability that three or four customers will arrive during the next 30 minutes

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4 years ago