Answer:
a) Micheal's present age = 8 years old
b) The sum of their ages in 6 years time = 63 years.
Step-by-step explanation:
From the above question, we know that
Rui feng is 3 years old
We are told that
• Michael is 5 years old than Rui feng
Micheal's present age is calculated as:
= 5 + Rui feng's age
= 5 + 3 = 8 years
• Vishal is thrice as old as Micheal
Vishal's present age is calculated as
= 3(Micheal age)
= 3(8)
= 24 years.
The sum of their ages in six years time
= ( 3 + 6) +( 8 + 6) + ( 24 + 6)
= 18 + 15 + 30
= 63 years
Therefore, a) Micheal's present age = 8 years old
b) The sum of their ages in 6 years time = 63 years.
Answer:
Explanation:
From the question, we have it that the probability of heads coming up every time or tail coming up every time is 1:7 if the coin is tossed in 4 tosses
What this means is that we have a probability of 1/8 of head showing up and a probability of 7/8 that a tail will show up in each toss of the coin
For four throws, it means all four are heads or all four are tails
If all four are heads, we have the probability of this happening as:
if all four are tails, we have the probability as:
Now, the probability of either heads or all tails after 4 tosses will be:
Let, number of double rooms and single rooms are d and s.
d + s = 26 ....1 )
Hotel rents double rooms at $34 per day and single rooms at $27 per day.
34d + 27s = 807 ....2)
Solving equation 1 and 2, we get :
34( 26 - s ) + 27s = 807
884 - 34s + 27s = 807
7s = 77
s = 11
And d = 26 - 11 = 15
Therefore, number of double rooms and single rooms are 15 and 11.
Hence, this is the required solution.
122.5.
A=b x h/2. A=122.5 b=7
A x b=h
122.5 x 7 =122.5
