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motikmotik
3 years ago
13

Jim and Em baked 33 macaroons.

Mathematics
1 answer:
bearhunter [10]3 years ago
4 0

Answer: 19 macaroons

Step-by-step explanation:

Let's create an equation to represent this situation. Let x represent the number of macaroons that Em made.

33=x+x+5

33=2x+5

33-5=2x+5-5

28=2x

28/2=2x/2

14=x

This means that Em made 14 macaroons.

14+5=19

Therefore, Jim baked 19 macaroons.

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How do you factor the common factor out of 30x^2-12x
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4 0
3 years ago
The sequence$$1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,\dots$$consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s i
kicyunya [14]

Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.


Recall the formula for the sum of consecutive positive integers,

\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2

Now,

1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016

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In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

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numbers, and their sum is

\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of 1+9\times2=19.

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8 0
2 years ago
Point G is on line segment{FH}
Angelina_Jolie [31]

Answer:

FG = 7

Step-by-step explanation:

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8x+1=9

8x = 8

x = 1

FG = 5(1)+2 = 7

8 0
3 years ago
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