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scZoUnD [109]
3 years ago
11

PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST

Mathematics
1 answer:
MaRussiya [10]3 years ago
6 0

Answer: 6773.27

Step-by-step explanation: volume formula for the cone is pie(radius)^2(height/3) just plug in your information into the formula and viola

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Fill in each box with the correct number or variable.
Licemer1 [7]

Answer:

8 would be there.

Step-by-step explanation:

am sorry i cant explain cause my battery is really low

4 0
3 years ago
What is the simplified form of (6^2+4)-15
suter [353]
First solve the parentheses and you get 36+4 which is 40 and then subtract 15 so you get 25
5 0
3 years ago
A universal set U consists of elements. If sets​ A, B, and C are proper subsets of U and ​n(U)​, ​n(A ​B)​n(A ​C)​n(B ​C)​, ​n(A
iragen [17]

Answer:

n(A\ u\ B) = 10

n(A'\ u\ C) = 10

n(A\ n\ B)' = 6

Step-by-step explanation:

Given

n(U) = 12

n(A\ n\ B) =n(A\ n\ C) = n(B\ n\ C) =6

n(A\ n\ B\ n\ C)=4

n(A\ u\ B\ u\ C)=10

Required

Solve a, b and c

There are several ways to solve this; the best is by using Venn diagram (see attachment for diagram)

Solving (a):

n(A\ u\ B)

This is calculated as:

n(A\ u\ B) = n(A) + n(B) - n(A\ n\ B)

From the attachment

n(A) = 0+2+4+2 = 8

n(B) = 0+2+4+2 = 8

n(A\ n\ B) = 4 +2 = 6

So:

n(A\ u\ B) = 8 + 8 - 6

n(A\ u\ B) = 10

Solving (b):

n(A'\ u\ C)

This is calculated as:

n(A'\ u\ C) = n(A') + n(C) -n(A'\ n\ C)

From the attachment

n(A) = n(U) - n(A) = 12 - 8 = 4

n(C) = 0+2+4+2 = 8

n(A'\ n\ C) = 2

So:

n(A'\ u\ C) = 4 + 8 - 2

n(A'\ u\ C) = 10

Solving (c):

n(A\ n\ B)'

This is calculated as:

n(A\ n\ B)' = n(U) - n(A\ n\ B)

n(A\ n\ B)' = 12- 6

n(A\ n\ B)' = 6

3 0
3 years ago
No entiendo ayudaaaa
hram777 [196]
This is a pythagorean theorem problem therefore a^2+b^2=c^2
a=8, b=?, c=10
8^2+b^2=10^2
64+b^2=100
100-64=56
square root of b^2=square root of 56
b=2 rad14
2 rad14 +4=
2 (rad14 + 1)= ANSWER
4 0
3 years ago
A student is training for the swim team during July and August one summer. She swims one hour every day, while averaging 800 met
Alex787 [66]

Step-by-step explanation:

Please find the attachment.

Let x be the number of hours the student swims per day.

We have been that a student swims one hour every day, so in 2 months the student will swim 60 hours.

We are also told that the student swims 800 meters each day. This means that slope of the graph that represents the total meters swam during the time of her training program will be 800.          

So in 60 days the student will swim 60\times 800=48,000\text{ meters}.

We can see from our attached graph that at x equals 60 our y is approximately 48.

Since y-axis represents the number of meters in thousands, so 48 stands for 48,000.

Therefore, attached graph is the right choice.

3 0
3 years ago
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