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Schach [20]
3 years ago
15

Evaluate the following expression

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
8 0

Answer:

2 {x}^{2}  - 5xy -  {y}^{3}  \\ x =  - 3 \\ y =  - 2 \\ 2 { (- 3)}^{2}  - 5  \times  - 3 \times  - 2 -  { (- 2)}^{3}  \\ 2 \times 9  +  - 30  -  - 8 \\  = 18 - 30 + 8 \\  =  - 4 \\ thank \: you

vaieri [72.5K]3 years ago
7 0

H ;-)

x = -3 and y = -2

2x² - 5xy - y³ =

= 2 · (-3)² - 5 · (-3) · (-2) - (-2)³ =

= 2 · 9 - 30 - (-8) = 18 - 30 + 8 =

= -12 + 8 = <u>-4</u>

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irga5000 [103]

Answer:

No, she cannot use a ratio of 21 to 6. You can figure this out in a few different ways. First you can simplify down the fraction 18/3, to get 6/1. 6/1 does not equal 21/6, because 21/6 equals 7/2. However, 6/1 it does equal 36/6. You could also noticed that three doubles to make six, yet 18 does not double to make 21. :D



Step-by-step explanation:


6 0
4 years ago
189*199 pls solve QUICK
amid [387]

Answer:

37611

Step-by-step explanation:

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3 0
3 years ago
Seven less than twice a number is 43. What is the number?
Mariana [72]

Answer:

25

Step-by-step explanation:

x = the number

2x - 7 = 43

    +7      +7

-----------------

2x = 50

------------

2        2

<u>x = 25</u>

6 0
2 years ago
Please solve with steps.
Kitty [74]

Answer: a) h = 2

              b) a = -\dfrac{3}{4}     k = \bold{3\dfrac{1}{2}}

<u>Step-by-step explanation:</u>

The vertex form of a quadratic equation is: y = a(x - h)² + k     where

  • a is the vertical stretch
  • (h, k) is the vertex

The graph shows the axis of symmetry at x = 2, therefore, the x-coordinate of the vertex (h) is 2.

Two points are given: \bigg(0, \dfrac{1}{2}\bigg)\ and\ \bigg(3, 2 \dfrac{3}{4}\bigg) . We can use these points to create two equations and then solve the system to find the a and k-values.

y = a(x - 2)² + k

\bigg(0, \dfrac{1}{2}\bigg)\\\rightarrow \dfrac{1}{2}=a(0-2)^2+k\\\\\rightarrow \dfrac{1}{2}=4a+k\\\\\rightarrow \dfrac{1}{2}-4a=k\\\\\\\bigg(3, 2\dfrac{3}{4}\bigg)\\\rightarrow 2\dfrac{3}{4}=a(3-2)^2+k\\\\\rightarrow 2\dfrac{3}{4}=a+k\\\\\rightarrow 2\dfrac{3}{4}-a=k\\\\\\\\\dfrac{1}{2}-4a=2\dfrac{3}{4}-a\\\\\dfrac{1}{2}-2\dfrac{3}{4}=4a-a\\\\\dfrac{2}{4}-\dfrac{11}{4}=3a\\\\-\dfrac{9}{4}=3a\\\\-\dfrac{9}{4\cdot 3}=\dfrac{3a}{3}\\\\ \bold{-\dfrac{3}{4}=a}

Solve for k:

2\dfrac{3}{4}-a=k\\\\\\2\dfrac{3}{4}-\bigg(-\dfrac{3}{4}\bigg)=k\\\\\\\bold{3\dfrac{1}{2}=k}

5 0
3 years ago
In the figure AB = BC = CD = DA 2 3.2 units. The slope of AB is. What else do
statuscvo [17]

Answer:

B) AD = 1/3 is the answer.

4 0
3 years ago
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