Five divided by the difference of a number and 12 equals the quotiene of 10 and the sum of the number and five
Compose the quadratic condition in standard shape, ax2 + bx + c = 0. Recognize the values of a, b, c. Write the Quadratic Equation. At that point substitute within the values of a, b, c. Simplify. Check the arrangements.
Answer:
B. (2,8), because both equations intersect at this point
41+0.10x = 31+0.15x
10 +0.10x=0.15x
10=0.05x
x=10/.05
x= 200 text messages
check 200*0.10 = 20 +41 =61
200*0.15 = 30+31 = 61
they equal each other so number of texts is 200
Answer: option 1.
Explanation:
feasible region is that region which is formed by the lines of constraints.
feasible region is shaded in the attached graph
inequalities becomes equalities to draw the graph
and lines will head towards the origin if constraint satisfied by putting x= 0, y=0
and on the contrary lines will move away from origin when condition of constraint does not satisfied.
