Answer:
133 fishes
Step-by-step explanation:
Units of food A = 400 units
Units of food B = 400 units
Fish Bass required 2 units of A and 4 units of B.
Fish Trout requires 5 units of A and 2 units of B.
i. For food A,
total units of food A required = 2 + 5
= 7 units
number of bass and trout that would consume food A = 2 x 
= 114.3
number of bass and trout that would consume food A = 114
ii. For food B,
total units of food B required = 4 + 2
= 6 units
number of bass and trout that would consume food B = 2 x 
= 133.3
number of bass and trout that would consume food B = 133
Thus, the maximum number of fish that the lake can support is 133.
Answer:
2x^2yz + 3xy^3z - 3xyz^3
Step-by-step explanation:
First you must distribute:
xyz(2x) + xyz(3y^2) + xyz(-3z^2)
Then simplify:
2xyxx + 3xyzy^2 - 3xyz * z^2
And finally simplify each term:
2x^2yz + 3xy^3z - 3xyz^3
Answer:
1/25
Step-by-step explanation:
square has 4 sides, if you add them all up you get 4/5.
1/5+1/5+1/5+1/5=4/5
so each side is 1/5
Area=length * width
A=1/5*1/5=1/25
Answer:
-1/3 - (-5/12) = 1/12.
Step-by-step explanation:
Simpler equation:
6/12 + (-5/12) = 1/12
Or This:
6/12 - 5/12 = 1/12.
hope this helped.
Answer:
y = -3 m = -1 b = 3
Step-by-step explanation:
-3y=3x-9
To isolate the y variable, divide both sides by -3.
y = -1x + 3
y = -3
m = -1
b = 3