Answer:
64w^4 - 48w^2 + 9
Step-by-step explanation:
<em>(I rearranged the terms so I could solve it easier)</em>
<u>Expanding the square:</u>
(-8w^2 + 3)^2
(-8w^2 + 3)(-8w^2 + 3)
<u>Combining like terms:</u>
64w^4 - 24w^2 - 24w^2 + 9
64w^4 - 48w^2 + 9
<u>Final answer:</u> 64w^4 - 48w^2 + 9
Answer:
The function is nonlinear
Step-by-step explanation:
Given
x --- y
1 --- 6
2 --- 24
3 --- 54
4 --- 96
Required
Determine if the function is linear of not
A function is linear if the difference in the successive y values are the same for corresponding values of x
When x = 1; y = 6 and when x = 2; y = 24
When x = 2; y = 24 and when x = 3; y = 54
When x = 3; y = 54 and when x = 4; y = 96
Note that the calculated differences are not equal.
<em>Hence, the function is nonlinear</em>
4 gigabytes because 71-50= 21 4*5=20
Answer:
Step-by-step explanation:
<u>Circumference formula</u>
<u>Solving for radius</u>
- 64 = 2*3.14r
- r = 64/2*3.14
- r = 10.19 ft
N=2
The smallest value of f(x) on [0, π/2] is 2, which occurs at x = 0. The smallest value of f(x) on [π/2, π] is also 0, which occurs at x = π. So the lower sum is (π/2)(2 + 2) = 2π
The largest value of f(x) on [0, π/2] is 3, which occurs at x = π/2. This is also true for the interval [π/2, π]. So the upper sum is (π/2)(3 + 3) = 3π
n = 4:
f '(x) = cos(x), which is positive for [0, π/2) and negative for (π/2, π]. This tells us that f is an increasing function on [0, π/2) and a decreasing function on (π/2, π]. So for the lower sum you will always evaluate f at the left endpoint of the subinterval if that subinterval lies in [0, π/2], and at the right endpoint of the subinterval if it lies in [π/2, π]
Thus, the lower sum for n = 4 is
(π/4)(f(0) + f(π/4) + f(3π/4) + f(π))
and the upper sum is
(π/4)(f(π/4) + f(π/2) + f(π/2) + f(3π/4)).
the lower sum for n=8 is
(π/8)(f(0)+f(π/8)+f(π/4)+f(3π/8)+f(5π/8...
and the upper sum is
(π/8)(f(π/8)+f(π/4)+f(3π/8)+f(π/2)+f(π/...