No 199 is not divisible by 9. If you were to divide 119 by 9 you would get 13.222222222
Let the numbers be x, x + 1 and x + 2.
From the information given:-
x(x + 1)(x + 2) = x^3 + 85
Solving for x:-
x(x^2 + 3x + 2) = x^3 + 85
x^3 + 3x^2 + 2x = x^3 + 85
3x^2 + 2x - 85 = 0
3x^2 - 15x + 17x - 85 = 0
3x(x - 5) + 17(x - 5) = 0
(3x + 17)(x - 5) = 0
x = -17/3 , 5
We take x = 5 because x is an integer.
Answer:- the 3 integers are 5, 6 and 7.
If you apply the or both
Only 1 of the students would need to know the "or both", therefore maximizing the remaining amount of students you can put in.
Gerald, let's call him, knows French AND German, so there's only one less student that knows french and german. Gerald is 1 student.
MAXIMUM:
There are now 14 monolinguistic French speakers and 16 monolinguistic German's, 30 students + Gerald=31.
Minimum:
As a bonus, the minimum is 15 students knowing french AND German and only 2 monolinguistic German speakers, so 17.
The correct answer is A im pretty sure
Answer:
45 minutes
Step-by-step explanation:
since 5 item--> 3 min
make a proportion
5/3=75/x
x=45