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finlep [7]
3 years ago
9

PLS HELP SHOW ME HOW TO DO THIS

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
5 0
The answer is 4! So c
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Which of the following is the equation of a line perpendicular to the line y = -10x + 1, passing through the point (5,7)?
Viktor [21]
Line 1;
y=-10x+1
Gradient m= -10
Gradient of line 2= 1/10
\frac{y-5}{x-7} = \frac{1}{10}
y-5=\frac{1}{10} {x-7}
y-5=\frac{1}{10} x- \frac{7}{10}
y=\frac{1}{10} x- \frac{43}{10}

6 0
3 years ago
Read 2 more answers
Question 9:
Arte-miy333 [17]

Answer:

I think the answer is.. .

Step-by-step explanation:

(b)

7 0
2 years ago
Which expression is equivalent to (sin x + 1)(sin x − 1)? A. cos2x B. -cos2x C. cos2x + 1 D. cos2x − 1 E. -cos2x + 1
Semenov [28]

ANSWER

B.

- \cos^{2} x

EXPLANATION

The given expression is

(sin x + 1)(sin x − 1)

Note that:

(x + 1)(x - 1) =  {x}^{2}  - 1

This implies that,

( \sin \: x + 1)( \sin \: x - 1)  =   \sin^{2} x - 1

We can factor -1 on the right hand side to get,

( \sin \: x + 1)( \sin \: x - 1)  =    - (1 - \sin^{2} x )

Note that from the Pythagorean Identity

1 - \sin^{2} x = \cos^{2} x

We apply this identity to obtain:

( \sin \: x + 1)( \sin \: x - 1)  = - \cos^{2} x

The correct choice is B

4 0
3 years ago
Thethree sides of a triangle measure 810 and 12 units is this a right angle?
Alja [10]

Answer:

The given triangle is NOT A RIGHT ANGLED TRIANGLE.

Step-by-step explanation:

Here, the three given sides of the triangle are:

8 units, 10 units and 12 units

Now, for any triangle to be a right angle:

by the PYTHAGORAS THEOREM:

(Base)^2 + (Perpendicular)^2  = (Hypotenuse)^2

The longest of all sides id the hypotenuse.

⇒ H  = 12 units

Let us assume, B = 8 units, P = 10 units

Now, here checking the condition:

(8)^2  + (10)^2  = 64  + 100  = 164  \neq (12)^2  = 144\\\implies (B)^2  + (P)^2  \neq (H)^2

Hence, the given triangle is NOT A RIGHT ANGLED TRIANGLE.

4 0
3 years ago
B+c= someone help please
trasher [3.6K]

Answer:

Is there any more to the problem but BC could be the answer it depends on what your supposed to be looking for

Step-by-step explanation:

4 0
3 years ago
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