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3 years ago

15

Triangle G Y K is shown. Angle G K Y is a right angle. Angle K G Y is 60 degrees and angle G Y K is 30 degrees. The length of G

K is 27.Given right triangle GYK, what is the value of tan(G)?

1 answer:

Karo-lina-s [1.5K]3 years ago

3 0

Answer:

Sqrt 3

Step-by-step explanation:

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3 years ago

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Solve for x in the equation x2-8x+41=0

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Answer:

d) 4 ± 5i

Step-by-step explanation:

Here we have to use the quadratic formula.

x = $\frac{-b +/- \sqrt{b^2 - 4ac} }{2a}$

In the given equation x^2 - 8x + 41 = 0, a =1, b = -8 and c = 41

Now plug in the given values in the above formula, we get

x = $\frac{-(-8) +/- \sqrt{(-8)^2 - 4*1*41} }{2*1}$

Simplifying the above, we get

x = $\frac{8 +/- \sqrt{64 - 164} }{2}$

x = $\frac{8 +/- \sqrt{-100} }{2}$

[√-100 = √-1 *√100 = i*10 = 10i] because the value of √-1 = i]

x = (8 ± 10i )/2

Now dividing by 2, we get

x = 4 ± 5i

The answer is d) 4 ± 5i

Hope you will understand the concept.

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2 years ago

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Can you please help me??

Sergio039 [100]

Answer:

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Step-by-step explanation:

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2 years ago

A group of 24 students have recess together. They are making teams to play a game. Each team has to have exactly 5 players, and

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They can make 4 teams and have 4 players that won’t be in a team.

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3 years ago

Identify the "inside function" u = f(x) and the "outside function" y = g(u). Then find dy/dx using the Chain Rule.

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DfLet $f(x)=\sec x$ and $g(x)=\sqrt x$ . Then

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$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm du}\dfrac{\mathrm du}{\mathrm dx}$

where $u=g(x)=\sqrt x$ , so that $y=f(g(x))=f(u)=\sec u$ . We have

$\dfrac{\mathrm du}{\mathrm dx}=\dfrac1{2\sqrt x}$
$\dfrac{\mathrm d\sec u}{\mathrm du}=\sec u\tan u$

and so

$\dfrac{\mathrm dy}{\mathrm dx}=\sec u\tan u\dfrac{\mathrm dy}{\mathrm du}=\dfrac{\sec\sqrt x\,\tan\sqrt x}{2\sqrt x}$

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2 years ago