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murzikaleks [220]
3 years ago
15

Find the length of the segment AB. Plz help!!! I’ll give you brainliest.

Mathematics
2 answers:
avanturin [10]3 years ago
7 0

Answer:

Its 5 i think? You just count how many units from point A to Point B is.

Mars2501 [29]3 years ago
7 0
The answer to the question is be 5
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Manager Roberts watched from the dugout as her baseball team took the field. It was the ninth inning and her players were locked
Roman55 [17]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

Some of the data is missing in the question, which is defined in attached. please find it.

For point 1: P - 8- Roe  

For point 2:  C - 1- Schmoe

For point 3: 1B - 4 - Blow

For point 4: 2B - 2 - Kent

For point 5: SS - 9 - Kowalski

For point 6: 3B - 3 - Simmons

For point 7: LF - 5 - Schmidt

For point 8: CF - 6 - Kitt

For point 9: RF - 7 - Whitt

7 0
3 years ago
Sasha ran 2/3 of a 27km race before she stopped to walk. How
dimaraw [331]

Answer:

2/3 of 27=18 km

Step-by-step explanation:

3 0
3 years ago
PLEASE, PLEASE, PLEASE HELP ME ITS URGENT AND I WILL GIVE BRAINLIEST TO THE FIRST CORRECT ANSWER. I HAVE A TEST TOMORROW.
Leno4ka [110]

Answer:

Step-by-step explanation:

let number of adult tickets=x

and number of student tickets=y

x+y=137   ...(1)

8x+6y=952

divide by 2

4x+3y=476   ...(2)

multiply by 3

3x+3y=411   ....(3)

(2)-(3) gives

x=65

y=137-65=72

number of adult tickets=65

number of student tickets=72

2.

let number of rose flowers =x

and number of carnation flowers=y

x+y=264

y=264-x

3.50 x+2.50y=772

multiply by 2

7x+5y=1544

7 x+5(264-x)=1544

7 x+1320-5 x=1544

2 x=1544-1320

2 x=224

x=112

y=264-112=152

number of rose flowers=112

number of carnation flowers=152

8 0
3 years ago
Need help with this someone send the answer please i don't understand why there are so many boxes.
Inessa05 [86]

Answer: See the attached image below. I've filled in the table with the proper values.

Row 2: AFB = 36, BFC = 54, EFA = 144

Row 3: AFB = 40, BCF = 50, DFE = 40

=======================================================

Explanation:

angles AFB and BFC add to 90 degrees since they form a right angle.

In row 1, we see that 48+42 = 90

Angles AFB and DFE are congruent since they are vertical angles. For row 1, we have both of these angles equal to 48 degrees.

Also for row 1, we have angles BFC and CFD add to 42+90 = 132, which is exactly the measure of angle BFD. This angle is congruent to angle EFA because they are vertical angles. So that's how angle EFA is 132.

--------------------------

Now onto row 2

We'll use the ideas of row 1 to work our way backwards to fill in the missing items.

We're given DFE is 36 degrees. This must mean that AFB is also 36 degrees. These angles are vertical angles.

Then we'll use the idea that (angleAFB)+(angleBFC) = 90 to find that

angle BFC = 90 - (angle AFB) = 90 - 36 = 54

Lastly for this row, we can say,

angle BFD = (angle BFC) + (angle CFD) = 54 + 90 = 144

angle EFA = angle BFD = 144

To summarize the missing items of row 2, we have...

  • angle AFB = 36
  • angle BFC = 54
  • angle EFA = 144

---------------------------

Now onto row 3. We use the same tricks (more or less) that were used on row 2.

If angle EFA is 140, then so is angle BFD. These are vertical angles.

(angle BFC) + (angle CFD) = angle BFD

(angle BFC) + 90 = 140

angle BFC = 140-90

angle BFC = 50

This in turn lets us say,

(angle AFB) + (angle BFC) = 90

angle AFB = 90 - (angle BFC)

angle AFB = 90 - 50

angle AFB = 40

angle DFE = angle AFB = 40

To summarize the missing pieces we found:

  • angle AFB = 40
  • angle BFC = 50
  • angle DFE = 40

All of the values are filled in the table shown below.

7 0
3 years ago
Here are the dimensions of the oven tray Jenny bakes the cakes on 600mm by 500mm. Each cake tin is 25 cm in diameter. How many c
storchak [24]
Given:
2 shapes: rectangle (tray) and circle (cake tin)

We need to find the area of each shape.

We need to convert mm to cm. 1mm = 0.1cm
600mm x 0.1cm/1mm = 60cm
500mm x 0.1cm/1mm = 50cm

Area of the Tray = 60cm * 50cm = 3,000cm²

Area of the cake tin = π r²
r = d/2 = 25/2 = 12.5cm

Area of the cake tin = 3.14 * (12.5cm)²
Area of the cake tin = 3.14 * 156.25cm²
Area of the cake tin = 490.625cm²

Area of the tray ÷ Area of the cake tin = number of cake tins that fit
3,000cm² ÷ 490.625cm² = 6.11 or 6 cake tins.

Only 6 cake tins Jenny can fit on the oven tray at one time.
7 0
4 years ago
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