What you need to do is find the greatest amount (1) and the lowest amount (1/4) of sap collected and the find how many times the lowest can go into the greatest. (So how many times can 1/4 go into 1). I believe that this is how you would do that.
Given set S = <span>{A, B, C, D, E, F, G, H}
There are 8 elements in set S and we are to choose 3 letters at random, the number of ways to choose such is x. It is simply similar to choosing 5 letters at random, which is also equal to x. Since order doesn't matter, n! / (n-m)! where n = 8 and m = 3, which is 336 ways. </span>
False. The postulate states: If two <span>
parallel</span> lines
are cut by a transversal, the interior angles on
the same side of the transversal are
supplementary.
Hey there!
Let's first find an easier situation.
If we're saying:
How many fives are in ten?
We're doing 10 divided by 5, because we're seeing how many 5's go into 10.
It's no different here.
We will be doing 6 divided by 3/4, just as we did with our simpler situation.
Using our "keep, switch, flip" rule (keep first term, change to multiplication, take reciprocal of second term)
we get:
6 divided by 3/4
=
6 * 4/3
= 24/3
= 8 3/4's in 6.
Hope this helps!
16, 36, 40
Set the problem up as 4x+9x+10x= 92
26x= 92
X= 4
Plug back in to get the lengths of the sides (shown above)
