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3 years ago

2(X -7) +10 word form

Mathematics

1 answer:

frez [133]3 years ago

4 0

Here igy homie pick one both r right

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Can I get some help please

lys-0071 [83]

Answer:

Step-by-step explanation:

C is the right answer that you're looking for because the hundredth value in this number is 3 in 345 and the closest hundredth there is 300 so the number closest to hundredths is 2,684,300

7 0

4 years ago

Read 2 more answers

Sally has 13 baseball cards in each week her grandpa bring 7 more sally created this equation y=7x +13 use the equation to answe

fiasKO [112]

Answer:

13 means the starting number

13 is the y-intercept (0,13)

5 0

3 years ago

The question is :

vovikov84 [41]

You are correct, the profit is modeled by:
-0.1t² + 6t + 67

We are also told that "t" is the number of years after 2010. So in 2016, the value of t will be 6. We substitute this into the equation we formed:

-0.1(6²) + 6(6) + 67
= 106.6 thousand dollars

3 0

4 years ago

Help please n thanks

garri49 [273]

Answer:

The answer I would choose is c

Hope this helped :)

5 0

3 years ago

How many Solutions does this system have? (1 point)

mixas84 [53]

The given system of equation that is $2x+y=3$ and $6x=9-3y$ has infinite number of solutions.

Option -C.

<u>Solution:</u>

Need to determine number of solution given system of equation has.

$\begin{array}{l}{2 x+y=3} \\\\ {6 x=9-3 y}\end{array}$

Let us first bring the equation in standard form for comparison

$\begin{array}{l}{2 x+y-3=0} \\\\ {6 x+3 y-9=0}\end{array}$

$\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$

To check how many solutions are there for system of equations $a_{1} x+b_{1} y+c_{1}=0 \text{ and }a_{2} x+b_{2} y+c_{2}=0$ , we need to compare ratios of $\frac{a_{1}}{a_{2}}, \frac{b_{1}}{b_{2}} \text { and } \frac{c_{1}}{c_{2}}$

In our case,

$a_{1} = 2, b_{1}= 1\text{ and }c_{1}= -3$

$a_{2} = 6, b_{2} = 3,\text{ and }c_{2} = -9$

$\begin{array}{l}{\Rightarrow \frac{a_{1}}{a_{2}}=\frac{2}{6}=\frac{1}{3}} \\\\ {\Rightarrow \frac{b_{1}}{b_{2}}=\frac{1}{3}} \\\\ {\Rightarrow \frac{c_{1}}{c_{2}}=\frac{-3}{-9}=\frac{1}{3}} \\\\ {\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}=\frac{1}{3}}\end{array}$

As $\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$ , so given system of equations have infinite number of solutions.

Hence, we can conclude that system has infinite number of solutions.

5 0

3 years ago

2(X -7) +10￼ word form

2(X -7) +10 word form