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Dafna1 [17]
2 years ago
6

The area of bdc in 3 significant figures please help asap

Mathematics
1 answer:
Genrish500 [490]2 years ago
6 0

Answer:

bro try using the COSINE rule

Step-by-step explanation:

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Jim bought a shirt for $27.00. He paid a 3.4% tax. How much did he pay in total?
ira [324]
27× .034=.918
You add this on
27.918
You have to round since cents (get it).
$27.92
8 0
2 years ago
Please help!!!!!!!!!
victus00 [196]

Answer:

None of the above

Explanation:

To find the type of lines they create, first find the slope of the equations.(Change form to y intercept)

4x-2y=-5

-2y=-4x-5

y=2x+(5/2)

Slope=2

-2x+3y=-3

3y=2x-3

y=(2/3)x-1

Slope=2/3

So, one has slope=2 and the other has slope=2/3. They’re not parallel because slopes are not the same. They’re not perpendicular because the slopes are not opposites. They’re not equal because their equations are not the same. So, none of the above.

6 0
3 years ago
Labeling Parts of a Circle
mel-nik [20]

Answer:

Click on the screenshot, I labeled the parts

Hope this helps :))

7 0
2 years ago
A cylinder has a radius of 6 inches and a height of 15 inches. What is the surface area of the cylinder? Express the answer in t
shutvik [7]

Answer:

The surface area for this cylinder is 252*pi square inches.

Step-by-step explanation:

The surface area of a cylinder can be calculated by using the following formula:

surface area = 2*pi*r² + 2*pi*r*h

Applying the data from the problem, we have:

surface area = 2*pi*(6)² + 2*pi*(6)*15

surface area = 2*pi*36 + 180*pi

surface area = 72*pi + 180*pi

surface area = 252*pi

The surface area for this cylinder is 252*pi square inches.

4 0
3 years ago
Read 2 more answers
Help, i just need the answers and no need for explanations.
maria [59]

Answer:

The equation of the quadratic function shown is;

x^2+ 2x -3

Step-by-step explanation:

Here in this question, we need to know the quadratic equation whose graph was shown.

The key to answering this lies in knowing the roots of the equation.

The roots of the equation are the solution to the quadratic equation and can be seen from the graph at the point where the quadratic equation crosses the x-axis.

The graph crosses the x-axis at two points.

These are at the points x = -3 and x = 1

So what we have are;

x + 3 and x -1

Multiplying both will give us the quadratic equation we are looking for.

(x + 3)(x-1) = x(x -1) + 3(x-1)

= x^2 -x + 3x -3 = x^2 + 2x -3

3 0
3 years ago
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