What is the answer to this?

How can i solve 5×23×2

VARVARA [1.3K]

multiply 5 and 2 then that with 23.

5x2=10 23x10=230

3 0

3 years ago

Read 2 more answers

Two large and 1 small pumps can fill a swimming pool in 4 hours. One large and 3 small pumps can also fill the same swimming poo

kolezko [41]

Let x and y be the unit rates at which one large pump and one small pump works, respectively.

Two large/one small operate at a unit rate of

(1 pool)/(4 hours) = 0.25 pool/hour

so that

2x + y = 0.25

One large/three small operate at the same rate,

(1 pool)/(4 hours) = 0.25 pool/hour

x + 3y = 0.25

Solve for x and y. We have

y = 0.25 - 2x ==> x + 3 (0.25 - 2x) = 0.25

==> x + 0.75 - 6x = 0.25

==> 5x = 0.5

==> x = 0.1

==> y = 0.25 - 2 (0.1) = 0.25 - 0.2 = 0.05

In other words, one large pump alone can fill a 1/10 of a pool in one hour, while one small pump alone can fill 1/20 of a pool in one hour.

Now, if you have four each of the large and small pumps, they will work at a rate of

4x + 4y = 4 (0.1) + 4 (0.05) = 0.6

meaning they can fill 3/5 of a pool in one hour. If it takes time t to fill one pool, we have

(3/5 pool/hour) (t hours) = 1 pool

==> t = (1 pool) / (3/5 pool/hour) = 5/3 hours

So it would take 5/3 hours, or 100 minutes, for this arrangement of pumps to fill one pool.

6 0

3 years ago

The ages of the people who came to a birthday party are shown below. Which statements must be true according to the histogram? C

spayn [35]

From the histogram it can be seen that
1.) the data is not qualitative. (Qualitative data is typically descriptive data and is not measured by a number but age is measured by a number).
2.) The data is not skewed right. (For a right skewed distribution, the tail of the distribution on the right hand (positive) side is longer than on the left hand side).
3.) There were 31 people at the party. (The total number of people at the party from the histogram is given by the sum of the heights of the bars of the histogram = 5 + 13 + 8 + 3 + 2 = 31).
4.) There were children at the party. (From the histogram, there were 5 poeple aged 20 and below, which we can describe as children).
5.) The most common age of the attendees was not 13 years old. (The mode (i.e. most occuring frequency) of a distribution is represented by the height of the tallest bar of the histogram. From the histogram, the tallest bar represents the ages between 21 to 40)
6.) The majority of the people at the party were less than 61 years old. (From the histogram, there were 5 + 13 + 8 = 26 people below the age of 61 in the party and 3 + 2 = 5 people above the age of 60 in the party).

Therefore, the statements that must be true according to the histogram are
There were 31 people at the party.
There were children at the party.
and
The majority of the people at the party were less than 61 years old.

5 0

2 years ago

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Help! i need the answer to this question plsss NO LINKS AND NO DOING IT JUST FOR THE POINTS Will give brainliest to the first se

Alex_Xolod [135]

2745

Step-by-step explanation:

solve it like simultaneously

180x+120y greater than 5145

180x+120y greater than 2400

eliminate x

y will now be greater than 2745

5 0

3 years ago

Convert 2.4 kg into cg. Please show your work.

strojnjashka [21]

The solution to the problem is as follows:

kilo -> 1000
centi -> 100


2.4 x 1000 g = 24 x 100 g. 

So, on the left we have 2.4 kg, and on the right we have 24 cg

I hope my solutions has come to your help. Thank you and have a nice day ahead!

7 0

3 years ago