Answer:
PG ≅ SG (Given)
PT ≅ ST (Given)
GT = GT (Common)
∴ ∠GPT ≅ ∠GST (SSS Congruency Axiom)
Step-by-step explanation:
<u>Given</u>: PG ≅ SG and PT ≅ ST
<u>To Prove</u>: ∠GPT ≅ ∠GST
<u>Proof</u>: PG ≅ SG (Given)
PT ≅ ST (Given)
GT = GT (Common)
∴ ∠GPT ≅ ∠GST (SSS Congruency Axiom).
<u>SSS Congruency Axiom</u>: If three pairs of sides of two triangles are equal in length, then the triangles are congruent.
<u>Congruence</u>: Two sets of points are called congruent if, and only if, one can be transformed into the other by an isometry, i.e., a combination of rigid motions, namely a translation, a rotation, and a reflection. This means that either object can be repositioned and reflected (but not resized) so as to coincide precisely with the other object. Two triangles are congruent if their corresponding sides are equal in length, and their corresponding angles are equal in measure.
1/3 + 7x = 1/3 + 7(5 )=
1/3+35
=1/3 + 105/3 =
106/3=
35 1/3
Ok so this is conic sectuion
first group x's with x's and y's with y's
then complete the squra with x's and y's
2x^2-8x+2y^2+10y+2=0
2(x^2-4x)+2(y^2+5y)+2=0
take 1/2 of linear coeficient and square
-4/2=-2, (-2)^2=4
5/2=2.5, 2.5^2=6.25
add that and negative inside
2(x^2-4x+4-4)+2(y^2+5y+6.25-6.25)+2=0
factor perfect squares
2((x-2)^2-4)+2((y+2.5)^2-6.25)+2=0
distribute
2(x-2)^2-8+2(y+2.5)^2-12.5+2=0
2(x-2)^2+2(y+2.5)^2-18.5=0
add 18.5 both sides
2(x-2)^2+2(y+2.5)^2=18.5
divide both sides by 2
(x-2)^2+(y+2.5)^2=9.25
that is a circle center (2,-2.5) with radius √9.25
The answer: The absolute value
58 - its simple- Hope I helped :)
