The distance around a circle

devlian [24]

A. multiply all the numbers together to find the possible outcomes

4 x 4 = 16

There are 16 different jacket-shirt outfits Ardell have.

They will not be the same color = 4 x 3

4 x 3 = 12

12/16 = 0.75, or a 75% chance they will not be the same color

hope this helps

6 0

3 years ago

Read 2 more answers

A professor thinks that the students in her statistics class this term are less creative than most students at this university.

choli [55]

Answer:

It is not enough evidence to reject null hypothesis. It is not enough evidence to say that mean score is not equal to 35.

Step-by-step explanation:

$\mu=35\\n=23\\\=x=33\\s=5\\\alpha=0.1$

1. Null and alternative hypothesis

$H_{0}:\mu=35\\H_{1}:\mu$

2. Significance level

$\alpha=0.1\\1-\alpha=0.99$

Freedom degrees is given by:

$v=n-1\\v=23-1=22$

For a sgnificance level of 0,01 and 22 freedom degrees, t-student distribution value is:

$t_{0.01;23}=-2. 5083$

3. Test statistic

$t=\frac{\=x-\mu}{\frac{s}{\sqrt{n} } }$

$t=\frac{33-35}{\frac{5}{\sqrt{23} } }$

$t=-1,918$

In this case, we have an one left tailed analysis, it means that null hypothesis is rejected if $t$

$-1.918>-2.5083$

Conclusion:

It is not enough evidence to reject null hypothesis. It is not enough evidence to say that mean score is not equal to 35.

3 0

2 years ago

Rabies is a viral disease of mammals transmitted through the bite of a rabid animal. The virus infects the central nervous syste

lisabon 2012 [21]

Answer:

(a) The value of x is 0.30.

(b) The probability that a reported case of rabies is not a raccoon is 0.45.

(c) The probability that a reported case of rabies is either a bat or a fox is 0.15.

Step-by-step explanation:

Denote the events as follows:

R = reported case of rabies is a raccoon

F = reported case of rabies is a fox

B = reported case of rabies is a bat

O = reported case of rabies is a some other animal.

The data provided is:

P (R) = 0.55

P (F) = 0.11

P (B) = 0.04

P (O) = x.

(a)

A property of a probability distribution is that the sum of all individual properties is 1.

That is, $\sum P(X)=1$

Compute the value of x as follows:

$\sum P(X)=1\\P(R)+P(F)+P(B)+P(O)=1\\0.55+0.11+0.04+x=1\\0.70+x=1\\x=1-0.70\\x=0.30$

Thus, the value of x is 0.30.

(b)

The probability of the complement of an event is the probability of its not happening.

$P(A^{c})=1-P(A)$

Compute the probability that a reported case of rabies is not a raccoon as follows:

$P(R^{c})=1-P(R)\\=1-0.55\\=0.45$

Thus, the probability that a reported case of rabies is not a raccoon is 0.45.

(c)

Compute the probability that a reported case of rabies is either a bat or a fox as follows:

$P(B\cup F)=P(B)+P(F)\\=0.11+0.04\\=0.15$

Thus, the probability that a reported case of rabies is either a bat or a fox is 0.15.

4 0

3 years ago

the volume V of a gas at a constant temperature varies inversely with the pressure P. when the volume is 100 cubic inches the pr

fiasKO [112]

Answer:

The pressure is $20\ psi$

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form $y*x=k$ or $y=k/x$

In this problem we have

$V*P=k$

where

V is the volume of a gas at a constant temperature

P is the pressure

we have

For $V=100\ in^{3}$ , $P=25\ psi$

step 1

Find the value of k

substitute the values of V and P

$100*25=k$

$k=2,500$

The equation is equal to $V*P=2,500$

step 2

Find the pressure when the volume is 125 cubic inches

For $V=125\ in^{3}$

substitute in the equation and solve for P

$125*P=2,500$

$P=2,500/125=20\ psi$

8 0

3 years ago

Comparing Standard Deviations

inessss [21]

Explanation:

There may be a couple of reasons for this:

1. Each team represents a sample of the players in the league. The averages of (random) samples can be expected to have a standard deviation that is smaller than the population standard deviation by a factor related to sample size.

2. A team average will result from the players who are played the most. Each team can be expected to field players more often whose averages are among the highest. The standard deviation of a set of the top tier of players will necessarily be smaller than the standard deviation of the set of all players.

8 0

3 years ago