Whatwhat is Monopoly how price and output determination under it
1 answer:
You might be interested in
The acceleration of the pendulum mass D is; r"_d = [x''(t) + lθ'' cos θ - lθ'² sin θ]i - l[θ'' sin θ - θ'² cos θ]j
<h3>What is Kinematics of particles?</h3>Kinematics is the study of the geometry of motion of particles, rigid bodies, etc., disregarding the forces associated with these motions. However, Kinematics of a particle is the motion of a point in space.
From the sample problem, we can solve it using the (x, y, z) coordinate system to get;
r_c = x(t) i
r_d = [x(t) + l sin θ]i + l cos θ j
Finding the first derivative of r_d gives velocity as;
r'_d = [x'(t) + lθ' cos θ]i - lθ' sin θ j
Taking the second derivative of r_d gives the acceleration as;
r"_d = [x''(t) + lθ'' cos θ - lθ'² sin θ]i - l[θ'' sin θ - θ'² cos θ]j
A sample problem of kinematics of particles is;
A block C slides along the horizontal rod, while a pendulum attached to the block can swing in the vertical plane. Find the acceleration of
the pendulum mass D.
Read more about Kinematics of Particles at; brainly.com/question/26269548
#SPJ1
An unsaturated solution is formed when 80. Grams of a salt is dissolved in 100. Grams of water at 40. °c. This salt could be.
Solubility is the maximum amount of soluble solid that can be dissolved in a 100-gram of water at a specific temperature. The solubility of a compound is directly proportional to the temperature which means that more solids can be dissolved at a higher temperature. Moreover, a solution which has a concentration below its solubility is an unsaturated solution. When both concentration and solubility are the same, then the solution is saturated. Lastly, when the concentration of a solution is higher than the solubility at a specific temperature, then the solution is called supersaturated.
<em>I </em><em>hope</em><em> it</em><em> will</em><em> help</em><em> you</em>
<em></em>
<em>#</em><em>c</em><em>a</em><em>r</em><em>r</em><em>y</em><em>o</em><em>n</em><em>l</em><em>e</em><em>r</em><em>a</em><em>n</em><em>i</em><em>n</em><em>g</em>