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vovikov84 [41]
3 years ago
6

Louis has entered a column of expense values. What feature can he use to insert the total expenses at the end of the column?

Computers and Technology
1 answer:
vovangra [49]3 years ago
5 0
I think it’s B tho I’m not really sure
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IblMessage.txt=welcome to fiji.what is the error in the coding and what type of error is it?(explain)​
spin [16.1K]

Answer:

The correct syntax (assuming WinForms) is

lblMessage.Text = "Welcome to fiji";

The given statement fails to follow the syntax of literal strings, which should be in quotation marks. (depending on the framework and programming language, the txt property may also be incorrect, as well as the missing semi-colon).

8 0
3 years ago
Pls answer will give brainlest dont answer if you dont know Upload your 300-word essay containing the following: the definition
Rainbow [258]

Answer: oh hello human :) also PLEASE DONT KILL ME I’m answering this because the question was already answered already on another post

6 0
2 years ago
Can anyone help me with this coding?
Snezhnost [94]

Answer:

Need more details properly.

Explanation:

Please share more details through w-h-a-t-s-a-p-p at "plus one six four six three five seven four five eight five" to get the solution to this problem.

Thanks!

6 0
3 years ago
Suppose an initially-empty queue Q has performed a total of 32 enqueue operations, 10 front operations, and 15 dequeue operation
Natasha_Volkova [10]

Answer:

22

Explanation:

1. We are going to have at hand 32 Enqueue Operation, with 10 from front and 15 dequeue and 5 empty queue operation

2. You dequeued total number of 15-5 =10 elements since 5 dequeue did not change the state of the queue, so invariably 10 dequeue is done.

3. Next is to enqueued a total of 32 elements.

Enqueue Operation do not change the state(and Size) of the queue, and can be ignored.

4. To arrive at the Total Size of queue, we will have 32-10 = 22 at the end

Answer : 22 because its a 5 dequeue Operations.

6 0
3 years ago
3-Write a Python program that has subprograms nested four deep and in which each nested subprogram references local variables, v
vivado [14]

Answer:

Explanation:

Below is a little explanation to guide us through;

There are 4 nested methods : level 0, level 1, level 2, and level 3.

Before the methods, there's a global variable defined that can be accessed by all the methods.

Level 0:

This method uses global variable, creates a level 0 variable in its scope, this level 0 variable can be used by all underlying nested methods.

Level 1: this method uses global, level 0, and level 1 variable, which can be accessed by all underlying nested methods: level 2, level 3.

Level 2: similar to te previous ones, it also uses global, level 0, level 1 variables. And creates a level 2 variable that can be accessed by level 3 also.

Level 3:

This method uses all previously created variables, and creates a new level 3 variable.

Function calls:

As you can see, the function calls are part of the method scopes. So, in order to call level 3, we need to access level 2 (because it is getting called from level 2 scope), for level 2, we must call level 1, for which level 0 needs to be called.

So, level 0 is called, which gives its out put and calls level 1, which gives its own output and calls level 2 and so on till level 3 is also called.

CODE:

global_var = "global" #accessible to all functions

def level0():

level0_var = "level 0" #accessible to level 0,1,2,3

print();

print("Level 0 function:")

print("global variable: ",global_var)

print("local variable 0: ",level0_var)

def level1():

print();

print("Level 1 function:")

level1_var = "level 1" ##accessible to level 1,2,3

print("global variable: ",global_var)

print("local variable 0: ",level0_var)

print("local variable 1: ",level1_var)

def level2():

print();

print("Level 2 function:")

level2_var = "level 2" #accessible to level 2,3

print("global variable: ",global_var)

print("local variable 0: ",level0_var)

print("local variable 1: ",level1_var)

print("local variable 2: ",level2_var)

def level3():

print();

print("Level 3 function:")

level3_var = "level 3" #accessible to level 3

print("global variable: ",global_var)

print("local variable 0: ",level0_var)

print("local variable 1: ",level1_var)

print("local variable 2: ",level2_var)

print("local variable 3: ",level3_var)

level3()

level2()

level1()

level0()

attached is the result of the code, also take note of the indentations too

cheers i hope this helps!!!!!

5 0
3 years ago
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