∫( (sinx) / (2 - 3cosx)) dx.
From laws of integration: ∫ f¹(u) / f(u) du = In(f(u)) + constant.
d/dx (2 - 3cosx) = 0 -3(-sinx) = 3sinx.
1/3d/dx(2 - 3cosx) = (1/3)*3sinx = sinx.
∫ ((sinx) / (2 - 3cosx)) dx. = ∫ ((1/3) d/dx (2 - 3cosx) / (2 - 3cosx))dx
= 1/3 ∫ (d/dx (2 - 3cosx) / (2 - 3cosx))dx
= (1/3)ln(2 - 3cosx) + Constant.
Answer:
6'8
Step-by-step explanation:
Answer:
Reflection over y-axis.
Step-by-step explanation:
The transformation being described is a reflection across the y-axis since we would have to flip the signs of the x-values to transform the function. See pictures below.
Hope this helps.
<h3><u>Answer</u>:- </h3>

<h3><u>Solution:-</u></h3>
Since painting is done on outer surface of cubical block we will have to find its surface area which is given by-

- <u>where a is side of the cube </u>



Now,



Thus it would cost $ 307.2 to paint the entire cubical block.
(3-2i)(3+2i)
=9+6i-6i-4i^2
i^2=-1
=9-4(-1)
=9+4
=13
Hope this can help.