Question

Hey guys! Can someone help me! Geometry

Answer 1

$\\ \sf\longmapsto 3x+3x-2=46$

$\\ \sf\longmapsto 6x-2=46$

$\\ \sf\longmapsto 6x=46+2$

$\\ \sf\longmapsto 6x=48$

$\\ \sf\longmapsto x=\dfrac{48}{6}$

$\\ \sf\longmapsto x=8$

Answer 2

$\huge \boxed{\mathfrak{Question} \downarrow}$

• Write an equation to represent the value of x in the figure given.

$\huge \boxed{\mathfrak{Answer} \downarrow}$

• Given, < DAB = 46°
• From the figure we can see that, < DAB = < DAC + < CAB ⇨ equation 1.
• So, 46° = 3x° + 3x - 2° ⇨ equation 2.

Now, let's solve & find the value of x with equation 2.

$\large \sf \: 46° = 3x° + 3x - 2° \\ \large \sf \: 46 = 6x - 2 \\ \large \sf \:46 + 2 = 6x \\ \large \sf \:48 = 6x \\ \large \sf \: \frac{48}{6} = x \\ \large \boxed{\bf \:8 = x}$