Hey guys! Can someone help me! Geometry

Mathematics

2 answers:

grandymaker [24]3 years ago

8 0

$\\ \sf\longmapsto 3x+3x-2=46$

$\\ \sf\longmapsto 6x-2=46$

$\\ \sf\longmapsto 6x=46+2$

$\\ \sf\longmapsto 6x=48$

$\\ \sf\longmapsto x=\dfrac{48}{6}$

$\\ \sf\longmapsto x=8$

UkoKoshka [18]3 years ago

4 0

$\huge \boxed{\mathfrak{Question} \downarrow}$

Write an equation to represent the value of x in the figure given.

$\huge \boxed{\mathfrak{Answer} \downarrow}$

Given, < DAB = 46°
From the figure we can see that, < DAB = < DAC + < CAB ⇨ equation 1.
So, 46° = 3x° + 3x - 2° ⇨ equation 2.

Now, let's solve & find the value of x with equation 2.

$\large \sf \: 46° = 3x° + 3x - 2° \\ \large \sf \: 46 = 6x - 2 \\ \large \sf \:46 + 2 = 6x \\ \large \sf \:48 = 6x \\ \large \sf \: \frac{48}{6} = x \\ \large \boxed{\bf \:8 = x}$

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25. If mVYX = 276° and m angle UVX = (4x - 5),

katovenus [111]

Answer:

22.25 or 22

Step-by-step explanation:

360-276+=84

4x-5=84

4x=89

x=22.25 or 22

6 0

3 years ago

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Snezhnost [94]

As points, x-intercepts take the form $(x,0)$ , so to find the intercepts we can set $y=0$ and solve for $x$ .

$x\ln(x+e)=0\implies\begin{cases}x=0\\\ln(x+e)=0\end{cases}$

From the first equation alone, we already know that $x=0$ is a solution, which means one intercept is $(0,0)$ .

The second equation gives

$\ln(x+e)=0\implies e^{\ln(x+e)}=e^0\implies x+e=1\implies x=1-e$

so that the second intercept occurs at $(1-e,0)$ .

So if $a=0$ and $b=1-e$ , we have $a+b=1-e$ , giving C as the answer.