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3 years ago

The region bounded by chord and arc is called ________.

Mathematics

1 answer:

Bas_tet [7]3 years ago

7 0

The region bounded by a chord and an arc is known as a segment .

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I don’t know the answer I’m not that smart help<br><br>Thank you

Stolb23 [73]

Answer:

Step-by-step explanation:

The tiny squares equal to 12 already so it is already greater therefore x=0

6 0

3 years ago

Plz help, 15 points!

Eduardwww [97]

Answer:

$2x+3y=-6$

Step-by-step explanation:

Let the line is $y=mx+b$ where $m$ is slope and $b$ is $y-intercept$ .

The line is parallel to $2x+3y=3$ , slope of both the lines will be same.

Find the slope of $2x+3y=3$

$3y=3-2x\\y=-\frac{2}{3}x+1$

Slope of line $=-\frac{2}{3}$

$m=-\frac{2}{3}$

So the line will be $y=-\frac{2}{3}x+b$

It passes through $(3,-4)$ .

$-4=-\frac{2}{3}\times 3+b\\-4=-2+b\\b=-2\\$

Hence the line is $y=-\frac{2}{3}x-2$

$y=-\frac{2}{3}x-2\\3y=-2x-6\ \ \ \ \ \ \ (Multiply both sides by 3)\\2x+3y=-6$

6 0

3 years ago

In triangle JKL, tan(bº) =

VikaD [51]

This is the working outs

8 0

3 years ago

9) The length of segment AE is 12. Find the coordinate of E.

Mashcka [7]

Answer:

-18

Step-by-step explanation:

A is at -30. AE = 12

So, E is -30+12 = -18

6 0

3 years ago

Look at the picture I attached

kow [346]

Answer:

Step-by-step explanation:

hope this helps

6 0

3 years ago

Read 2 more answers