Answer: C. 541.60 hours
Step-by-step explanation:
Since the lifetime of a 2-volt non-rechargeable battery in constant use has a normal distribution, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = lifetime of the batteries.
µ = mean lifetime
σ = standard deviation
From the information given,
µ = 516 hours
σ = 20 hours
Looking at the normal distribution table, the z score corresponding to ninety percent approximately is 1.28
Therefore,
1.28 = (x - 516)/20
Cross multiplying by 20, it becomes
20 × 1.28 = x - 516
25.6 = x - 516
x = 516 + 25.6
x = 541.6
Therefore, Ninety percent of all batteries have a lifetime less than
541.60 hours
Answer:
C. m∠1 = m∠4
Step-by-step explanation:
A. m∠2 + m∠4 = 180°
∠2 and ∠4 are vertically opp. angles which means m∠2 = m∠4.
Hence, it's a <u>false</u> statement.
B. m∠2 + m∠3 = 180°
∠2 and ∠3 are corresponding angles which means m∠2 = m∠3.
It's a <u>false</u> statement.
C. m∠1 = m∠4
∠1 and ∠4 are another pair of corresponding angles which clearly states that m∠1 = m∠4.
Therefore, it's a <u>true</u> statement.
D. m∠1 = 90°
As clearly visible in the diagram;
It's a <u>false</u> statement.
88 multiplied by 106 is 9328 and move two decimal spaces to the left wich is 93.28% :)
Involving the second and no higher power of an unknown quantity or variable.
Siamone has $65.32 + DAN
Dan has CARLY - $37.50
CARLY = $127.75
Plug Carly into Dan's equation...
$127.75 - $37.50 = $90.20
DAN = $90.20
Plug Dan into Siamone's equation
$65.32 + $90.20 = $155.57
