1) Loida needs 37 meters of curtain cloth to decorate each window in the house. If there are 8

An ant crawls at a rate of 2 1/6 ft per minute. At this rate, how long does it take the ant to crawl a distance of 5 1/5 ft? Ent

tangare [24]

For 2 1/6 = 13/6 Ft, ant takes = 1 min.
So, for 1 ft, it takes = 6/13 min.

Now, for 5 1/5 = 26/5 min. it would take = 6/13 * 26/512/5 = 2.4 min

In short, Your Answer would be 2.4 min

Hope this helps!

3 0

3 years ago

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Mario has drawn a plan of his bedroom on 1 cm square paper. His en-suite shower cubicle measure. 1m x1m, give the scale of his d

Romashka [77]

Mario has drawn a plan of his bedroom on 1 cm square paper. His en-suite shower cubicle measure. 1m x1m, give the scale of his drawing
as ratio _ 1 cm__ : __1m_.
What are the actual dimension of his bed __1__ m x _1_ m

4 0

3 years ago

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Why was it not possible to increase the vertical scale by 0.5 each time ?

NNADVOKAT [17]

Answer:nothings not possible my friend (impossible)

Step-by-step explanation:

8 0

4 years ago

Raymond is collecting Beyblades. He begins with a total of 700 Beyblades but loses 360 Beyblades at a tournament. He represents

natta225 [31]

Answer:

Step-by-step explanation:

A bc he lost it so we’re subtracting and it says “700-360” underneath the problem.

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4 years ago

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An certain brand of upright freezer is available in three different rated capacities: 16 ft3, 18 ft3, and 20 ft3. Let X = the ra

ruslelena [56]

Answer:

$E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6$

$E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6=349.2$

$V(X) = E(X^2)-[E(X)]^2=349.2-(18.6)^2=3.24$

The expected price paid by the next customer to buy a freezer is $466

Step-by-step explanation:

From the information given we know the probability mass function (pmf) of random variable X.

$\left|\begin{array}{c|ccc}x&16&18&20\\p(x)&0.3&0.1&0.6\end{array}\right|$

Point a:

The Expected value or the mean value of X with set of possible values D, denoted by E(X) or μ is

$E(X) = $\sum_{x\in D} x\cdot p(x)$

Therefore

$E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6$

If the random variable X has a set of possible values D and a probability mass function, then the expected value of any function h(X), denoted by E[h(X)] is computed by

$E[h(X)] = $\sum_{D} h(x)\cdot p(x)$

So $h(X) = X^2$ and

$E[h(X)] = $\sum_{D} h(x)\cdot p(x)\\E[X^2]=$\sum_{D}x^2\cdot p(x)\\ E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6\\E(X^2)=349.2$

The variance of X, denoted by V(X), is

$V(X) = $\sum_{D}E[(X-\mu)^2]=E(X^2)-[E(X)]^2$

Therefore

$V(X) = E(X^2)-[E(X)]^2\\V(X)=349.2-(18.6)^2\\V(X)=3.24$

Point b:

We know that the price of a freezer having capacity X is 60X − 650, to find the expected price paid by the next customer to buy a freezer you need to:

From the rules of expected value this proposition is true:

$E(aX+b)=a\cdot E(x)+b$

We have a = 60, b = -650, and E(X) = 18.6. Therefore

The expected price paid by the next customer is

$60\cdot E(X)-650=60\cdot 18.6-650=466$

4 0

3 years ago