Answer:
Ki
Step-by-step explanation:
Answer: The total interest paid on the mortgage is $179550
Step-by-step explanation:
The initial cost of the property is $300000. If he deposits $30000, the remaining amount would be
300000 - 30000 = $270000
Since the remaining amount was compounded, we would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = 270000
r = 2% = 2/100 = 0.02
n = 12 because it was compounded 12 times in a year.
t = 25 years
Therefore,
A = 270000(1+0.02/12)^12 × 25
A = 270000(1+0.0017)^300
A = 270000(1.0017)^300
A = $449550
The total interest paid on the mortgage is
449550 - 270000 = $179550
The roots of the polynomial <span><span>x^3 </span>− 2<span>x^2 </span>− 4x + 2</span> are:
<span><span>x1 </span>= 0.42801</span>
<span><span>x2 </span>= −1.51414</span>
<span><span>x3 </span>= 3.08613</span>
x1 and x2 are in the desired interval [-2, 2]
f'(x) = 3x^2 - 4x - 4
so we have:
3x^2 - 4x - 4 = 0
<span>x = ( 4 +- </span><span>√(16 + 48) </span>)/6
x_1 = -4/6 = -0.66
x_ 2 = 2
According to Rolle's theorem, we have one point in between:
x1 = 0.42801 and x2 = −1.51414
where f'(x) = 0, and that is <span>x_1 = -0.66</span>
so we see that Rolle's theorem holds in our function.
