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Lostsunrise [7]
3 years ago
12

2n^3-3n^2+2n=oanswer needed urgently pls​

Mathematics
1 answer:
Kazeer [188]3 years ago
3 0

n = 0

Step-by-step explanation:

<h2><em>Factor the </em><em>expression</em></h2>

<em>2n ^ 3 - 3n ^ 2 + 2n = 0</em>

<h2><em>Separate into possible cases</em></h2>

<em>n(2n ^ 2 - 3n + 2) = 0</em>

<h2><em>Solve the equation</em></h2>

<em>n = 0[tex]n = 0 \:  \:  \:  \:  \:  \:  \:  \: [tex]n = 0 \:  \:  \:  \:  \:  \:  \:  \: 2n ^ 2 - 3n + 2 = 0</em>

<h2><em>Find the union</em></h2>

<em>n = 0[tex]n = 0 \:  \:  \:  \:  \:  \: [tex]n = 0 \:  \:  \:  \:  \:  \: n =  R</em>

<h2><em>there </em><em>for </em></h2>

<em>n = 0</em>

<em>hope </em><em>it</em><em> help</em>

<em>#</em><em>c</em><em>a</em><em>r</em><em>r</em><em>y</em><em> </em><em>on</em><em> learning</em>

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<h3>What is the Fundamental Counting Theorem?</h3>

It is a theorem that states that if there are n things, each with n_1, n_2, \cdots, n_n ways to be done, each thing independent of the other, the number of ways they can be done is:

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