Question

2n^3-3n^2+2n=oanswer needed urgently pls​

Answer 1

$n = 0$

Step-by-step explanation:

Factor the expression

$2n ^ 3 - 3n ^ 2 + 2n = 0$

Separate into possible cases

$n(2n ^ 2 - 3n + 2) = 0$

Solve the equation

$n = 0[tex]n = 0 \: \: \: \: \: \: \: \: [tex]n = 0 \: \: \: \: \: \: \: \: 2n ^ 2 - 3n + 2 = 0$

Find the union

$n = 0[tex]n = 0 \: \: \: \: \: \: [tex]n = 0 \: \: \: \: \: \: n = R$

there for

$n = 0$

hope it help

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