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3 years ago

WILL MARK BRAINLIEST:

1 answer:

6 0

A) harry spent 5/8 of his pocket money

b) harry has 3/8 of his pocket money left

HOW I DID IT
basically we want to add fractions in the first part so ( 1/2 + 1/8 ) to do this you have to make the denominator equal (number on the bottom) so to get 2 to 8 you have to multiply it by 4 and whatever you do to the bottom you have to do to the top so you multiply the top by 4 as well that gives you 4/8 + 1/8 and you just add the top numbers then you find out the difference for the second part of the equation

You might be interested in

Is 3.61 less than 3.87

My name is Ann [436]

Step-by-step explanation:

yes because 61 is less than 87

5 0

3 years ago

What is 0.00000802 in scientific notation

salantis [7]

$0.00000802=8.02 \cdot 10^{-6}$

8 0

3 years ago

Using properties of logarithms in excersises 13-18, use the properties of logarithms o write the logarithm in terms of log3(5) a

Maslowich

Answer:

$log_3(\frac{21}{5}) = log_3(7) - log_3(5)+ 1$

Step-by-step explanation:

Given

$log_3(\frac{21}{5})$

Required

Express in terms of $log_3(5)$ and $log_3(7)$

$log_3(\frac{21}{5})$

Express 21 as 7 * 3

$log_3(\frac{21}{5}) = log_3(\frac{7 * 3}{5})$

Apply law of logarithm

$log_3(\frac{21}{5}) = log_3(7) + log_3(3) - log_3(5)$

$log_3(3) = 1$ . So, we have:

$log_3(\frac{21}{5}) = log_3(7) + 1 - log_3(5)$

Rewrite:

$log_3(\frac{21}{5}) = log_3(7) - log_3(5)+ 1$

4 0

3 years ago

A company did a quality check on all the packs of nuts it manufactured. Each pack of nuts is targeted to weigh 18.25 oz. A pack

IrinaVladis [17]

Answer:

$x < 17.89$ or $x > 18.61$ , since $\left | x-18.25 \right |>0.36$

Step-by-step explanation:

According to the question the weight is rejected if it is more than 0.36 oz, the weight should not be beyond 0.36 oz that is from the target weight of 18.25.

We can say that, the difference between the actual weight and the target weight is greater than 0.36 oz.

Lets say the actual weight is 'x'. So,

$x-18.25>0.36$

But there can be times when the actual weight 'x' could be less than 0.36, So the order will be changed:

$18.25-x>0.36$

The absolute value will sum up these two into a single inequality:

$|x-18.25|>0.36$

Simplifying the inequalities, we get:

$x-18.25>0.36$

$x>18.61$ (we have added 18.25 on both sides)

$18.25-x>0.36$

Subtracting 18.25 from both the sides we get:

$-x>-17.89$

After sign change it is:

$x$

So we can see that only $x < 17.89$ or $x>18.61$ since $\left | x-18.25 \right |>0.36$ is the one that represents the scenario given above.

5 0

4 years ago

Explain your answer !! <br> Have a nice day <br><br> Will give braisnlt

Jet001 [13]

Answer:

(5,7)

Step-by-step explanation:

The given system of equations are :

6x-2y = 16

3x-y = 8 ....(1)

3x = 15

x = 5 ...(2)

Put the value of x in equation (1).

3(5)-y = 8

15-y=8

15-8 = y

y = 7

Put the value of y in equation (1).

3x-7 = 8

3x = 15

x = 5

So, the solution of the given system of equations are x = 5 and y = 7. i.e. (5,7).

6 0

3 years ago