Answer:
<em>Rachel will earn $85 in 10 hours.</em>
Step-by-step explanation:
Rachel earned $34 in 4 hours at her job today.
Suppose, she will earn
dollar in 10 hours tomorrow.
So, <u>according to ratio of 'dollar' and 'hours'</u>, the equation will be.....

After cross multiplying, we will get.....

Thus, Rachel will earn $85 in 10 hours.
Answer:
Step-by-step explanation:
If ali has 23 so Raina has 7 more than Ali = 23 + 7 = 30
And trey has 4 times as much as Ali = 23 x 4 = 92
Total = 92 + 23 + 30 = 145
Complete question is:
Seventy million pounds of trout are grown in the U.S. every year. Farm-raised trout contain an average of 32 grams of fat per pound, with a standard deviation of 7 grams of fat per pound. A random sample of 34 farm-raised trout is selected. The mean fat content for the sample is 29.7 grams per pound. Find the probability of observing a sample mean of 29.7 grams of fat per pound or less in a random sample of 34 farm-raised trout. Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.
Answer:
Probability = 0.0277
Step-by-step explanation:
We are given;
Mean: μ = 32
Standard deviation;σ = 7
Random sample number; n = 34
To solve this question, we would use the equation z = (x - μ)/(σ/√n) to find the z value that corresponds to 29.7 grams of fat.
Thus;
z = (29.7 - 32)/(7/√34)
Thus, z = -2.3/1.200490096
z = -1.9159
From the standard z table and confirming with z-calculator, the probability is 0.0277
Thus, the probability to select 34 fish whose average grams of fat per pound is less than 29.7 = 0.0277