4 years ago

How do I solve this twice the difference of a number and seven is less than or equal to forty

Mathematics

2 answers:

EastWind [94]4 years ago

7 0

Answer:

2(x-7)<=40

First, I will distribute the two. I will get 2x-14<=40. Then I will add 14 to both sides, getting 2x<=54. Next, I will divide2 by both sides and my answer will be x<=27.

max2010maxim [7]4 years ago

4 0

2 * (x-7) <= 40

x<=27

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