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TiliK225 [7]
3 years ago
10

How do I solve this twice the difference of a number and seven is less than or equal to forty

Mathematics
2 answers:
EastWind [94]3 years ago
7 0

Answer:

2(x-7)<=40

First, I will distribute the two. I will get 2x-14<=40. Then I will add 14 to both sides, getting 2x<=54. Next, I will divide2 by both sides and my answer will be x<=27.

max2010maxim [7]3 years ago
4 0
2 * (x-7) <= 40

x<=27


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I have to solve this: (2x + 2/5)+(5x-4/5) and then simplify it.
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 35x - 2

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Step-by-step explanation:

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At Friday's football game, 1,294 tickets were sold for a total amount of $8,816.00. If each student ticket costs $5.00, and each
NeTakaya

Answer:

512 student tickets.

Step-by-step explanation:

Let x be number of student tickets and y be number of adult tickets.

We have been given that at Friday's football game 1,294 tickets were sold. We can represent this information as:

x+y=1294...(1)

We are also told that each student ticket costs $5.00, and each adult ticket costs $8.00 and 1,294 tickets were sold for a total amount of $8,816. We can represent this information as:

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Substituting this value in equation (2) we will get,

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Therefore, 512 student tickets were purchased at Fridays football game.

6 0
3 years ago
A movie theater sold 2,604 tickets in 6 days. they sold the same number of tickets each day. How many tickets did the theater se
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Step-by-step explanation:

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5 0
3 years ago
The solution set for <br> 6a^2-a-5=0
Alex_Xolod [135]

Answer:

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Step-by-step explanation:

I'm going to attempt to factor 6a^2-a-5

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Find two numbers that multiply to be a*c and add to be b.

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So replace -a with -6a+5a in the expression we started with

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now we factor by grouping

6a(a-1)+5(a-1)

(a-1)(6a-5)

Now let's solve the equation:

(a-1)(6a-5)=0

So a=1 or a=5/6

4 0
3 years ago
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